Answer:
Change in specific internal Energy
Explanation:
Given:
- Mass of the gas, m=0.4 lb
- Initial pressure and volume are

- Final pressure and temperature are

- Heat transfer from the gas is 2.1 Btu
Since the process is isotropic we have

So the final volume of the gas is calculated.
Work in any isotropic is given by w

According to the first law of thermodynamics we have

So the Specific Internal Change is given by

So the specific Change in Internal energy is calculated.
To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzmann law which establishes that a black body emits thermal radiation with a total hemispheric emissive power (W / m²) proportional to the fourth power of its temperature.
Heat flow is obtained as follows:

Where,
F =View Factor
A = Cross sectional Area
Stefan-Boltzmann constant
T= Temperature
Our values are given as
D = 0.6m

The view factor between two coaxial parallel disks would be


Then the view factor between base to top surface of the cylinder becomes
. From the summation rule


Then the net rate of radiation heat transfer from the disks to the environment is calculated as





Therefore the rate heat radiation is 780.76W
You knew that this question is ridiculously easy. So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".
The description is talking about a parallel circuit. The other
kind is a series circuit, and that one has no forks in the road.
Answer:
Keeping the speed fixed and decreasing the radius by a factor of 4
Explanation:
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :

We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"
It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,
R' = R/4
New centripetal acceleration will be,




So, the centripetal acceleration of the ball can be increased by a factor of 4.
32 kg m/s would be the kinetic energy.