Answer:
Step-by-step explanation:
If the price after the discount is subtracted is $96.25 then this is what you do
u times 0.40 x 96.25 which is 38.5 so since you are wanting to know what the price was before the discount you would add 38.5 to 96.25 and when you do that your answer is 134.75
but if you are just trying to get the discount from 96.25 you subtract 38.5 from 96.25
Answer:
Step-by-step explanation:
We have that the polynomial, has a root of multiplicity 2 at x = 3 and a root of multiplicity 1 at x = -2.
This means the factored form of the polynomial will be.
Also, it was given that, the y-intercept is y=-12.6.
This implies that:
Divide both sides by 18;
Therefore the polynomial is
Answer:
∠1 is 90° because it is a right angle
To find angle 2, we must add the given angles and x then make the equation equal to 180°, which we next solve for x;
x + 90 + 30 = 180
x + 120 = 180
-120 -120
x = 60, ∠2 = 60°
Angle 5 is vertical to angle 1 which equals 90 degrees, and <u>vertical angles are congruent</u> meaning that they measure the same degrees so therefore ∠5 = 90°
Angles 4 and 40° are <u>vertical</u> to angle 2 which measures 60 degrees;
40 + x(where x equals angle 4) = 60
-40 -40
x = 20, ∠4 = 20°
Specified earlier, angles <u>40° and 4 are equal to 60°</u>, this means that angle three added to angles 40° and 4 will be equal to 90 degrees since angle 1 is 90 degrees and the other three angles will have to equal 90 degrees because they are supplementary.
So we set up the equation;
40 + 20(angle four) + x = 90
60 + x = 90
-60 -60
x = 30, ∠3 = 30°
Answer:
A) 21.02°
B) 26.74°
C) 22.79°
D) DNE
Step-by-step explanation:
We can solve the equation for the angle:
D = 672·sin(2θ)
D/672 = sin(2θ)
arcsin(D/672) = 2θ
θ = arcsin(D/672)/2
A) For D = 450, θ = arcsin(450/672)/2 = 21.0198° ≈ 21.02°
B) For D = 540, θ = arcsin(540/672)/2 = 26.7363° ≈ 26.74°
C) For D = 480, θ = arcsin(480/672)/2 = 22.7923° ≈ 22.79°
D) For D = 720, θ = arcsin(720/672)/2 = DNE
Answer:
5.196 m
Step-by-step explanation:
p = La perpendicular del triángulo es la longitud de la antena.
h = La hipotenusa del triángulo es la longitud del cable conectado a la parte superior del poste = 6 m
= Incline el cable con el suelo =
De las funciones trigonométricas sabemos que
La longitud de la antena es 5.196 m.