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Answer is C.
Calories would denote the amount of heat.
Givens are:
Mass = 500 g
t0 = 20C
tf = 30C
C = 1 cal/gC
Formula:
Q=MCt
500g (1cal/gC) 10C= 5000 cal
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Explanation: Technically the speed is an inch a second.
Answer:
The increase in the gravitational potential energy is 29.93 joules.
Explanation:
Given that,
Mass of the box, m = 2.35 kg
It is lifted from the floor to a tabletop 1.30 m above the floor, h = 1.3 m
We need to find the increase the gravitational potential energy. Initial it will placed at ground i.e. its initial gravitational potential is equal to 0. The increase in the gravitational potential energy is given by :


U = 29.93 Joules
So, the increase in the gravitational potential energy is 29.93 joules. Hence, this is the required solution.
A) 
The angular acceleration of the wheel is given by

where
is the initial angular velocity of the wheel (initially clockwise, so with a negative sign)
is the final angular velocity (anticlockwise, so with a positive sign)
is the time interval
Substituting into the equation, we find the angular acceleration:

And the acceleration is positive since the angular velocity increases steadily from a negative value to a positive value.
B) 3.6 s
The time interval during which the angular velocity is increasing is the time interval between the instant
where the angular velocity becomes positive (so,
) and the time corresponding to the final instant
, where
. We can find this time interval by using

And solving for
we find

C) 2.4 s
The time interval during which the angular velocity is idecreasing is the time interval between the initial instant
when
) and the time corresponding to the instant in which the velovity becomes positive
, when
. We can find this time interval by using

And solving for
we find

D) 5.6 rad
The angular displacement of the wheel is given by the equation

where we have
is the initial angular velocity of the wheel
is the final angular velocity
is the angular acceleration
Solving for
,
