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3 years ago

How many calories are absorbed by a pot of water with a mass of 500g in order to raise the temperature from 20c to 30c?

1 answer:

8 0

Calories would denote the amount of heat.

Givens are:
Mass = 500 g
t0 = 20C
tf = 30C
C = 1 cal/gC

Formula:
Q=MCt

500g (1cal/gC) 10C= 5000 cal

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What is the focal length of the eye-lens system when viewing an object at infinity? assume that the lens-retina distance is 2.0

34kurt

The focal length of the eye-lens system will be exactly 2.0 cm. The lens thickness is altered depending on the distance of the object being viewed so that the focal length is ALWAYS equal to the lens-retina distance. If this is not true fr an individual, they need glasses :)

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3 years ago

When your food is placed under a warming light in a fast food restaurant, which type of electromagnetic waves are most likely us

8090 [49]

B is the answer i pretty sure...

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3 years ago

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What would happen to the moon if earth stopped exerting the force of gravity on it?

Mila [183]

There are two equal forces of gravity between the Earth and the Moon.
One force pulls the Moon toward the Earth.
The other force pulls the Earth toward the Moon.

If only this gravity suddenly switched off, then the moon would
continue to orbit the Sun, very much as it does now.

If ALL gravity suddenly switched off, then . . .

-- the Moon would stop orbiting the Earth and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- the Earth would stop orbiting the Sun and would sail away, in
a straight line and at the speed it had when gravity disappeared;

-- all the gases surrounding the Earth ... which we call "air" ... would
start drifting away, and expanding into a giant cloud of gas, and stop
being an atmosphere;

-- the Sun would completely fall apart, expand into a giant cloud of gas,
and stop being a star.

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3 years ago

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Using planck's constant and a wavelength of 656e-9 what is the energy of the photon

lbvjy [14]

Answer:

3.03e-19 J

Explanation:

Use the formula E = hc/λ

Where:

h (Planck's constant) = 6.626e-34 J*s

c (speed of light, constant) = 3.00e8 m/s

λ (wavelength) = 656e-9 m

E = energy (in Joules)

E = (6.626e-34 * 3.00e8) / 656e-9 = 3.03018293e-19 = 3.03e-19 J

4 0

2 years ago

A block of mass m moving with a velocity v collides with a mass 2m at rest. Consider the collision is elastic, we have to find t

lions [1.4K]

Answer:

$vf_{1} =\frac{1}{3} v$ :Final block velocity (toward the left)

$vf_{2} =\frac{2}{3} v$ :Final mass velocity (to the right)

Explanation:

To solve this problem we apply the theory of shocks:

In an elastic shock the kinetic energy and the amount of linear movement or momentum are conserved.

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1.

Principle of conservation of the momentum:

m1vi1+m2vi2=m1vf1+m2vf2 Equation 1

Formula to calculate the coefficient of elastic restitution (e):

$e=\frac{vf_{2}-vf_{1} }{vi_{1}-vi_{2} }$ Equation 2

m1: Block mass

m2: mass of the body that collides with the block

Vi1,vf1: initial, final velocity of the block

Vi2,vf2: initial, final velocity of the body that collides with the block

Of the problem data we know that:

m1=m , m2 = 2m, vi1=v and vi2=0, then, we replace this information in equation (1) :

mv+0=mvf1+2mvf2 we divide by m:

v=vf1+2vf2 Equation (3)

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1,then , we we replace this information in equation (2)

$1=\frac{vf_{2}-vf_{1} }{v-0}$

v=vf2-vf1 Equation (4)

vf2=v+vf1 Equation (5)

We replace the equation 5 in the equation (3)

v=vf1+2(v+vf1)

v=vf1+2v+2vf1

-3vf1=v

$vf_{1} = -\frac{1}{3} v$

We replace Vf1=(-1/3)v in the equation (5):

$vf_{2} =v-\frac{1}{3} v$

$vf_{2} =\frac{2}{3} v$

Answer;

$vf_{1} =\frac{1}{3} v$ :Final block velocity (toward the left)

$vf_{2} =\frac{2}{3} v$ :Final mass velocity (to the right)

5 0

2 years ago