Answer:
The answer is B, although technically that is an eclipse.
Within the system of the same star, the period of a planet's orbit is
proportional to the 3/2 power of its distance from the central body.
(Kepler's empirical third law of planetary motion, promoted to being
etched in stone by Newton's gravitation.)
(4) ^ 3/2 = <em>8 times</em> as long.
Answer:
a) Ф = 0.016 N / C m
, b) q_{int} = 0.14 10⁻¹² C
Explanation:
a) For this problem we use Gauss's law
Ф = E .ds = /ε₀
The camp is in the x direction so it has no flow through the cylinder walls.
Ф = E A
The area of a circle is
A = π r
Ф = E π r
Ф = (x- 3.6) r
Let's calculate
Ф = (3.7 -3.6) 0.16
Ф = 0.016 N / C m
b) we clear from Gauss's law
q_{int} = Ф ε₀
Where the flow is on both sides, on the face at x = 0 the flow is zero
q_{int} = 0.016 8.85 10⁻¹²
q_{int} = 0.14 10⁻¹² C
Answer:
The net charges on inner surface is +3 C
The net charges on outer surface is +7 C
Explanation:
Given that,
Charge on spherical conducting shell = 10 C
Charge at center = -3 C
We know that,
The net electric field inside the conducting shell is zero. The Gaussian surface inside the conductor must have zero net charge.
We need to calculate the net charges on inner surface
The charge on the inner surface of the conductor must be equal and opposite to the present charge of the center.
So, The net charges on inner surface is +3 C.
We need to calculate the net charges on outer surface
Using formula of net charge
Put the value into the formula
Hence, The net charges on inner surface is +3 C
The net charges on outer surface is +7 C
Answer:
The correct answer is - B ≠ 0, E = 0.
Explanation:
A force q E is exerted by the electric field on the charged particle that accelerates always, that is, it increases the speed of the particle. The particle can never be rotated in a rotation in the circle in an electric field.
The magnitude of the velocity cannot be changed by the magnetic field but changes only the velocity of the direction.
If the particle moves in a circle it means that the speed should begin for a year. The only direct velocity is constant and only the change be b can be achieved. So, B ≠ 0 and E = 0.