Laws that implemented the consumers' right to be informed forbid __________.

Physics

2 answers:

Reptile [31]3 years ago

4 0

Laws that implemented the consumers' right to be informed forbid misleading advertising.

Answer is C.

lina2011 [118]3 years ago

3 0

Laws that implemented the consumers' right to be informed forbid misleading advertising.

Answer: Option C

<u>Explanation:</u>

The laws that are implemented to protect consumer’s rights include the things discussed below.

The advertisements about any product should be informative. It should provide valid advertisements about that product. It prohibits the act of advertising falsified information about the product.

Business sellers usually advertise their product with false information to cheat the customers and make them buy their product just to attain profit. They usually aim to sell the product without any advertised usage. So, this kind of act is highly prohibited by the laws of Consumer’s rights.

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professor190 [17]

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3 years ago

a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be

Natali [406]

The equivalent resistance of n resistors connected in parallel is given by
$\frac{1}{R_{eq}} = \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}$ (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is $R_{Eq}=2.00 \Omega$ , and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
$\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R} + \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{5}{R}$
From which we find $R= 5 \cdot 2 \Omega = 10 \Omega$ .

So, each piece of wire has a resistance of $10 \Omega$ . Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
$R_{Eq}=R_1 + R_2 + ...+R_n$
So if we apply it at our case, we have
$R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega$

therefore, the resistance of the original wire was $50 \Omega$ .