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pogonyaev
3 years ago
12

The expression 1/3b−1/3 factored is

Mathematics
2 answers:
expeople1 [14]3 years ago
6 0
(1/3)(b-1) is the simplest set of factors.

artcher [175]3 years ago
5 0

Answer:

\frac{1}{3}[b-1]

Step-by-step explanation:

we have

\frac{1}{3}b-\frac{1}{3}

Factor the coefficient \frac{1}{3} of both terms

\frac{1}{3}b-\frac{1}{3}=\frac{1}{3}[b-1]

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2. Lynn filled up her gas tank on the way home from work. She uses about 1.6
Gelneren [198K]

The amount of gas in her tank after 8 days given the linear equation g = 213 - 1.6d is 200.2 gallons of gas

<h3>Linear equation</h3><h3 />
  • Gallons of gas used per day = 1.6 gallons
  • Number of days = d
  • Quantity of gas = g

The equation

g = 213 - 1.6d

Gas remaining after 8 days

g = 213 - 1.6(8)

= 213 - 12.8

g = 200.2 gallons of gas

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5 0
2 years ago
Three planes intersect in ?
Anuta_ua [19.1K]

Answer:

The air

Step-by-step explanation:

4 0
3 years ago
find the mean, median, and mode of the data set. round to the nearest tenth. 7,7,14,15,4,1,7,2,15,9,5
Arisa [49]
Here is the mean, median, and mode:

Mean: 1+2+4+5+7+7+7+9+14+15+15 = 86/11 ≈ 7.82
Median: 7
Mode: 7

To find the mean add up all the numbers and divide by the number of numbers

To find the median you just keep on crossing of numbers left to right until you get the middle number

To find the mode just look at which number is most commonly seen

Hope this helps!
5 0
3 years ago
Read 2 more answers
What is the relation between the trigonometric ratios tan(R) and tan(J)? Please answer ASAP!
Ilya [14]

Step-by-step explanation:

∆PQR similar to ∆ JKL

JK/KL= PQ/QR

6/12=3/QR

QR=3×2= 6

therefore, tan(R) = PQ/QR = 3/6=1/2

and, tan(J) = KL/JK =12/6=2

\frac{ \tan(R) }{ \tan(J) }  =  \frac{ \frac{1}{2} }{2}

\frac{ \tan(R) }{ \tan(J) }   =  \frac{1}{4}

tan(J)=4.tan(R)

option D

6 0
3 years ago
Next 4 multiples of 1/6
solniwko [45]

Answer:

2/6 3/64/65/6

Step-by-step explanation:

5 0
3 years ago
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