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nasty-shy [4]
3 years ago
12

PLEASE HELP ME QUICK!!!20 POINTS!!!!!!!!

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

the volume scales by (1/10)^3. so it would be 48.875*10^-3.

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HELP ME PLS I DONT HAVE TIME
chubhunter [2.5K]

Answer:

A is true.......................b is false....................and c is false

Step-by-step explanation:

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2 years ago
Factor
stellarik [79]
C on that one which is the correct answer
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3 years ago
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Hey all you math geniuses can you help me with this question that should be easy
kenny6666 [7]

Answer:

(B) \frac{-3}{x}

Step-by-step explanation:

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7 0
3 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
5 1/6 divided by 2 5/12= 2 4/29 true or false
Alex_Xolod [135]
5 1/6 divided by 2 5/12 is 2 4/29 so it is true
3 0
3 years ago
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