Ask question

Ask question

All categories

4 years ago

6

Describe how solid liquid and gases particles are arranged

1 answer:

vaieri [72.5K]4 years ago

5 0

Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

You might be interested in

Differentiate between the various qualities of reagents which are ordinary ,analar and industrial quality reagent

dolphi86 [110]

The difference between ordinary, analar and industrial reagents is the in the purity. Ordinary reagents are those whose purity meets the standard. Analar reagents are used in chemical analysis and they are of high purity but with known contaminants which again illustrates their use in chemical analyses.Finally the industrial reagents are not pure enough and they are used for industrial purposes as well for commercial use.

4 0

4 years ago

Helga has a box. She wants to determine how much the box can hold. Which measurement should she calculate?

zaharov [31]

C) volume

Explanation:

hope it helps !

3 0

3 years ago

Read 2 more answers

Number 9<br> Please<br> Three molecules of the fatty acid in question 8…

Marianna [84]

My best bet is e because look how it is formed

6 0

3 years ago

A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL

snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43$

$pH = 14 - pOH = 14 - 4.43 = 9.57$

Now, the perchloric acid added will react with ammonia:

$n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles$

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O

$n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles$

Finally, we can calculate the pH of the resulting solution:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98$

$pH = 14 - 4.98 = 9.02$

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0

3 years ago

Plz help me with this question plzzzzz

LekaFEV [45]

Answer:

6

Explanation:

Formula: Al2O3

If we require 2Al2O3

We divide 2 by 3

Sorry for the shadow of phone and fingers.

8 0

3 years ago