<u>Answer:</u> The volume of
comes out to be 10.2625 mL.
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of
comes out to be 10.2625 mL.
NaCl - also known as sodium chloride or table salt; an ionic bond; it’s a chemical compound, so both
SO2 - also known as sulfur dioxide; a covalent bond; nonmetal
CaO - also known as calcium oxide; an ionic bond; metal
HF - also known as hydrogen fluoride; polar covalent; metal
NO2 - also known as nitrogen dioxide; covalent; nonmetal
H2O - also known as water; covalent; nonmetal
3 cubic centimeters, Volume= density/ mass
Answer:
72.0 mL of steam is formed.
Explanation:
The reaction is :

You can treat coefficient of compounds as amount of volume used.
Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.
For 1 mL of ammonia
(=1.25) mL of oxygen is used to form
(=1) mL of nitric oxide gas and
(=1.5) mL of steam.
OR
Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of
become one like this

We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :
<em>1. </em><em>Assume ammonia to be completely exhausted</em>
For 50 mL of ammonia
(= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.
2. <em>Assume oxygen to be completely exhausted</em>
For 60 mL of oxygen only
(=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.

Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form
(= 48) mL of nitic oxide gas and
(= 72) mL of steam.
Therefore <em>72 mL of steam </em>is formed.