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n200080 [17]
3 years ago
15

It takes 50.0 J to push a large box 4.00 m across a floor. Assuming the push is in the same direction as the move, what is the m

agnitude of the force on the box?
Physics
1 answer:
Blababa [14]3 years ago
8 0
<h3><u>Answer;</u></h3>

12.5 Newtons

<h3><u>Explanation;</u></h3>

Work done is defined as the product of force and distance covered or moved. It is measured in joules.

Work done = Force × distance

Therefore; making force the subject;

Force = work done/distance

         = 50.0 J/ 4.00 m

         =<u> 12.5 Newtons.</u>

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If a car goes down Lake at 30 miles per hour how far will it go in 0.25 hours?
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Answer:

7.5 miles

Explanation:

0.25 hours=15minutes.

So you do

30 miles=60minutes

x =15minutes

cross multiply

Ans-7.5

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A buoy is anchored to the ocean floor a large wave approaches the buoy how will the buoy move as the wave goes by
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7 0
3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
3 years ago
· A car moves at 12 m/s and coasts up a hill with a
Zigmanuir [339]

Explanation:

Given that,

Initial speed of a car, u = 12 m/s

Aceleration, a = -1.6 m/s²

(a) The displacement of car after 6 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 6+\dfrac{1}{2}\times (-1.6)\times 6^2\\\\d=43.2\ m

(b) The displacement of the car after 9 seconds is :

d=ut+\dfrac{1}{2}at^2\\\\d=12\times 9+\dfrac{1}{2}\times (-1.6)\times 9^2\\\\d=43.2\ m

Hence, this is the required solution.

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3 years ago
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