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2 years ago

If an astronaut is 66 kg, what is their weight in N on the moon?

2 answers:

6 0

Mass isn’t dependent on gravity, so the man would still be 66
66
k
g
. His weight, however, is calculated using the formula:

=
w
=
m
g

So, weight, equal mass times the acceleration due to gravity. On the moon, acceleration due to gravity is 1.62/²
1.62
m
/
s
²
. If we plug these “givens” in, we get:

=(66)(1.62/²)
w
=
(
66
k
g
)
(
1.62
m
/
s
²
)

Therefore, weight equals 106.92
106.92
N
e
w
t
o
n
s
(the unit of weight)

Blababa [14]2 years ago

5 0

The mass of the person would be 66 kg on both Earth and the Moon.

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2 years ago

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Jobisdone [24]

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2 years ago

. A 2.0-m wire carries a current of 15 A directed along the positive x axis in a region where the magnetic field is uniform and

Lady bird [3.3K]

Answer:

The resulting magnetic force on the wire is -1.2kN

Explanation:

The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is

F = I (L*B)

Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)

L x B = $\left[\begin{array}{ccc}i&j&k\\2&0&0\\30&-40&0\end{array}\right]$ = (0, 0, -80)

we can now solve

F = I (L x B) = I (-80)

F = -1200 kmN

F = -1200 kN * 10⁻³

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6 0

2 years ago

Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st

DedPeter [7]

Answer:

E1 = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q) = +11nC

distance between thin glass rods = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = $\frac{Q}{2\pi e_{0}rL }$

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = $\frac{Q}{2\pi e_{0}rL }$ $( \frac{1}{0.01} - \frac{1}{0.03} )$ ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )