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3 years ago

3 types of acceleration

Physics

2 answers:

emmasim [6.3K]3 years ago

5 0

3 types of acceleration are changes in speed, direction, and both simultaneously.

Svetach [21]3 years ago

5 0

Three types of acceleration are speeding up, slowing down, and turning. I have attached a photo that can help explain.

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Which is in the Moneran kingdom? A. plants B. bacteria C. animals D. mushrooms

Stells [14]

Answer: b

Explanation:

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3 years ago

During an observation, it was noticed that light travels as bundles containing certain amounts of energy. What does this evidenc

blsea [12.9K]

Answer: B. It demonstrates a behavior or particles.

Explanation: I took the test and got it right

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4 years ago

A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b

Artist 52 [7]

Answer:

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = u m/s

Acceleration = 0 $m/s^2$

So $4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}$

Now at time 2t,

$S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm$

So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = 0 m/s

Acceleration = -g $m/s^2$

$4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}$

At time 2t,

$S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm$

So vertical distance traveled in time 2t = 16 cm to the bottom

6 0

3 years ago

A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina

TiliK225 [7]

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

$P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\$

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

*The options are provided for a different question where

3 0

4 years ago

Determine the wavelengths for Potassium (violet, λ = 400 nm) and Strontium (red, λ = 700 nm) light emissions. Calculate the freq

TEA [102]

Answer:

For Potassium:

Frequency = 7.5 x 10¹⁴ Hz; E (energy) = 8.83 x 10⁻²¹ J

For Strontium:

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = 2.85 x 10⁻¹⁹ J

Explanation:

Wavelength is represented by λ, and Frequency is represented by ν .

E (energy) = hν = hc/λ, where ν = frequency; c = speed of light = 3 x 10⁸ m/s; 1 s-1 = 1 Hz

h = planck's constant = 6.62 x 10⁻³⁴ J.s; 1 nm = 10⁻⁹ m

1. Potassium λ (wavelength) = 400 nm, Frequency, ν is given by :

ν = c/λ = (3 x 10⁸ m/s) / 400 nm

= (3 x 10⁸ m/s) / 400 x 10⁻⁹ s-1

= 0.0075 x 10¹⁷s-1

= 7.5 x 10¹⁴ s-1

Frequency = 7.5 x 10¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (7.5 x 10¹⁴s-1)

E (energy) = 8.83 x 10⁻²¹ J

2. Strontium λ (wavelength) = 700 nm ,Frequency, ν is given by :

ν = c/λ = (3 x 10⁸ m/s) / 700 nm

= (3 x 10⁸ m/s) / 700 x 10⁻⁹s-1

= 0.00428571428 x 10¹⁷s-1

= 4.3 x 10¹⁴ s-1

Frequency = 4.3 x 0¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (4.3 x 0¹⁴s-1)

E (energy) = 2.85 x 10⁻¹⁹ J

4 0

3 years ago

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