The difference is actually a result of the the depth. Ponds, according to limnology (the study of water bodies) are shallow enough where plants could conceivably grow across the entire surface. ... As a result, there are some very small bodies of water, less than an acre that are deep enough to be called lakes.
Answer:
The water molecules slow down, stronger attractions form between them, and the molecules are pulled closer together.
Explanation:
In solids the packing of the particles is closer and tighter thus increasing the intermolecular attraction. This makes solids rigid with a definite shape, size and volume. On the other hand in liquids the packing of the particles is loose thus decreasing the intermolecular attraction. This makes liquids able to flow, and takes the shape and volume of the container in which they are placed.
Answer:
The sample of lithium occupies the largest volume.
Explanation:
Given the densities for the four elements, we have the expression
that shows the relationship between mass and Volume to express the density of an element.
For each element we have:
![d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL](https://tex.z-dn.net/?f=d_%7Blithium%7D%3D%5Cfrac%7Bm_%7Blithium%7D%7D%7BV_%7Blithium%7D%7D%3D0.53g%2FmL)
![d_{gold}=\frac{m_{gold}}{V_{gold}}=19.3g/mL](https://tex.z-dn.net/?f=d_%7Bgold%7D%3D%5Cfrac%7Bm_%7Bgold%7D%7D%7BV_%7Bgold%7D%7D%3D19.3g%2FmL)
![d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL](https://tex.z-dn.net/?f=d_%7Baluminum%7D%3D%5Cfrac%7Bm_%7Baluminum%7D%7D%7BV_%7Baluminum%7D%7D%3D2.70g%2FmL)
![d_{lead}=\frac{m_{lead}}{V_{lead}}=11.3g/mL](https://tex.z-dn.net/?f=d_%7Blead%7D%3D%5Cfrac%7Bm_%7Blead%7D%7D%7BV_%7Blead%7D%7D%3D11.3g%2FmL)
The problem says that all the samples have the same mass, so:
![m_{lithium}=m_{gold}=m_{aluminum}=m_{lead}=m](https://tex.z-dn.net/?f=m_%7Blithium%7D%3Dm_%7Bgold%7D%3Dm_%7Baluminum%7D%3Dm_%7Blead%7D%3Dm)
it means that m is a constant
Now, solving for the Volume in each element and with m as a constant, we have:
![V_{lithium}=\frac{m}{d_{lithium}}](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Blithium%7D%7D)
![V_{lithium}=\frac{1}{0.53\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D%5Cfrac%7B1%7D%7B0.53%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{lithium}=1.88\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D1.88%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{gold}=\frac{m}{d_{gold}}](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Bgold%7D%7D)
![V_{gold}=\frac{1}{19.3\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D%5Cfrac%7B1%7D%7B19.3%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{gold}=5.18*10^{-2}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D5.18%2A10%5E%7B-2%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{aluminum}=\frac{m}{d_{aluminum}}](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Baluminum%7D%7D)
![V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D%5Cfrac%7B1%7D%7B2.70%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D3.70%2A10%5E%7B-1%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
![V_{lead}=\frac{m}{d_{lead}}](https://tex.z-dn.net/?f=V_%7Blead%7D%3D%5Cfrac%7Bm%7D%7Bd_%7Blead%7D%7D)
![V_{lead}=\frac{1}{11.3\frac{g}{mL}} *m](https://tex.z-dn.net/?f=V_%7Blead%7D%3D%5Cfrac%7B1%7D%7B11.3%5Cfrac%7Bg%7D%7BmL%7D%7D%20%2Am)
![V_{lead}=8.85*10^{-2}\frac{mL}{g}*m](https://tex.z-dn.net/?f=V_%7Blead%7D%3D8.85%2A10%5E%7B-2%7D%5Cfrac%7BmL%7D%7Bg%7D%2Am)
If we assume m = 1g, we find that:
![V_{lithium}=1.88mL](https://tex.z-dn.net/?f=V_%7Blithium%7D%3D1.88mL)
![V_{gold}=5.18*10^{-2}mL](https://tex.z-dn.net/?f=V_%7Bgold%7D%3D5.18%2A10%5E%7B-2%7DmL)
![V_{aluminum}=3.70*10^{-1}mL](https://tex.z-dn.net/?f=V_%7Baluminum%7D%3D3.70%2A10%5E%7B-1%7DmL)
![V_{lead}=8.85*10^{-2}mL](https://tex.z-dn.net/?f=V_%7Blead%7D%3D8.85%2A10%5E%7B-2%7DmL)
So we can see that the sample of lithium occupies the largest volume with 1.88mL
Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.
|F| = 112 - 67 = 45 N
F = 45 N ( to the left)