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2 years ago

How can scientists use stoichiometry to ensure that commercial products contain the components that manufacturers claim they do?

Chemistry

1 answer:

Rina8888 [55]2 years ago

4 0

Answer:

I know you have been waiting awhile for this question to be answered :)

Stoichiometry is used in industry quite often to determine the amount of materials required to produce the desired amount of products in a given useful equation. Each one of these products requires stoichiometry. There would be no products from these industries without chemical stoichiometry.

Explanation:

Hopefully this helps :D

Sorry you had to wait so long :(

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Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi

Aleksandr [31]

Answer: -

3.3° C

Explanation: -

Mass of water m = 180.5 g

Energy released as heat Q = 2494 J

Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.

Specific heat of water Cp = 4.184 (J/g)⋅∘C

Using the formula

Q = m x Cp x ΔT

We get temperature change ΔT = Q / (m x Cp)

= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C

= 3.3° C

Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe

6 0

3 years ago

If a container were to have 24 molecules of C5H12 and 24 molecules of O2 initially, how many total molecules (reactants plus pro

frutty [35]

Answer:

81 molecules

Explanation:

The reaction between C5H12 and O2 is a combustion reaction and is represented by the following equation;

C5H12 + 8O2 --> 5CO2 + 6H2O

The ratio of C5H12 to O2 from the above equation is 1 : 8.

Aplying the conditins of the question; 24 molecules each of C5H12 and O2 we have;

3C5H12 + 24O2 --> 15CO2 + 18H2O

This means we have 24 - 3 = 21 molecules of C5H12 that are unreacted.

Total molecules is given as;

3(C5H12) + 24(O2) + 15(CO2) + 18(H2O) + 21(Unreacted C5H12) = 81 molecules

5 0

2 years ago

Why is it important to analyze data?

gayaneshka [121]

Answer:

It is important to analyze data to further understand what's going on. By analyzing data, you know more about what you are investigating. Without analyzing data, you may find it harder to figure something.

7 0

2 years ago

Que materias o asignaturas disciplinarias consideras que están

zalisa [80]

Las áreas temáticas que pueden estar involucradas en el cuidado del agua son;

Biología

Química

Geología

oceanografía

Geografía

Conservar y compartir es una parte integral de la ciencia ambiental. La ciencia ambiental en sí misma es multidisciplinaria.

Varias áreas temáticas deben estar involucradas en la conservación del medio ambiente.

Estas áreas temáticas incluyen;

Biología

Química

Geología

oceanografía

Geografía

Aprende más: brainly.com/question/10929764

5 0

2 years ago

6 Fe2+ (aq) + Cr2O72− (aq) + 14 H+ (aq) → 6 Fe3+ (aq) + 2 Cr3+ (aq) + 7 H2O (aq) If the titration of 23 mL of an iron(II) soluti

ratelena [41]

Answer:

1.047 M

Explanation:

The given reaction:

$6Fe^{2+}_{(aq)}+Cr_2O_7^{2-}_{(aq)}+14H^+_{(aq)}\rightarrow 6Fe^{3+}_{(aq)}+2Cr^{3+}_{(aq)}+7H_2O_{(aq)}$

For dichromate :

Molarity = 0.254 M

Volume = 15.8 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.8 ×10⁻³ L

Thus, moles of dichromate :

$Moles=0.254 \times {15.8\times 10^{-3}}\ moles$

Moles of dichromate = 0.0040132 moles

1 mole of dichromate react with 6 moles of iron(II) solution

Thus,

0.0040132 moles of dichromate react with 6 × 0.0040132 moles of iron(II) solution

Moles of iron(II) solution = 0.02408 moles

Volume = 23 mL = 0.023 L

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

<u>Molarity = 0.02408 / 0.023 = 1.047 M</u>

7 0

2 years ago