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Flauer [41]
3 years ago
11

PLEASE HELP IM FREAKING OUT What is the madd of as liquid with 12g and volume of 2 mL

Chemistry
1 answer:
nata0808 [166]3 years ago
8 0

24

Explanation:

we have the equation d = m/v so here the density is 12 and the volume is 2, 12 = m/2. in this situation we multiply 12×2= 24. The mass is 24.

Let's check if it works with the formula

24/2 = 12

12 = 24/2

yes. it works

the answer is mass = 24

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Question 5
Dafna11 [192]

The mass percent of oxygen is 32.82%.

<h3>What is a noble gas?</h3>

A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.

Let us now calculate the relative molecular mass of xenon tetraoxide.

Xe + 4 (O)

131 + 4(16) = 195

Given that the mass of oxygen in the compound is 64, the mass  percent of oxygen in xenon tetroxide is obtained from;

64/195 * 100/1

= 32.82%

Learn more about mass percent:brainly.com/question/5394922

#SPJ1

5 0
1 year ago
What phases are most common at high temperatures
Nikitich [7]

Answer:

Liquids and gases.

For most substances, when heated to a high enough temperature, the molecules begin moving faster which results in its liquid or gas state.

5 0
3 years ago
Which of the following statements best describes a difference between mechanical waves and electromagnetic waves?
kipiarov [429]
The correct answer is the 3rd one  
6 0
3 years ago
The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of
Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

 

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

5 0
3 years ago
A gas that exerts a pressure of
spayn [35]

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

P_1 = 15.6 psi

V_1 = ???

P_2 = 25.43 psi

V_2 = 1.895 L

Using Boyle's law:

P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\  V_1 = \dfrac{25.43 \times 1.895}{15.6}  \\ \\ \mathbf{  V_1 = 3.089  \ L}

4 0
3 years ago
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