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Flauer [41]
3 years ago
11

PLEASE HELP IM FREAKING OUT What is the madd of as liquid with 12g and volume of 2 mL

Chemistry
1 answer:
nata0808 [166]3 years ago
8 0

24

Explanation:

we have the equation d = m/v so here the density is 12 and the volume is 2, 12 = m/2. in this situation we multiply 12×2= 24. The mass is 24.

Let's check if it works with the formula

24/2 = 12

12 = 24/2

yes. it works

the answer is mass = 24

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Which combination of elements below will bond ionically and in the same ratio as lithium when it bonds to sulfur?
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1. Al+3 has how many neutrons?<br><br>2. thorium-230 has how many protons, neutrons and electrons?
Usimov [2.4K]

The mass number of aluminium is 26 and the atomic number of aluminium is 13.

The number of neutrons is given by the difference between the mass number and number of protons.

number of neutrons = mass number - number of protons

Number of protons = 13

Mass number of Aluminium = 26

Therefore number of neutrons = 26-13 = 13.

The atomic number of thorium is 90 and the mass number of thorium is 230 as given in the question

atomic number = number of electrons =  number of protons

Therefore the number of electrons in thorium 230 = 90

Number of protons in thorium 230 = 90

Number of neutrons = Mass number - number of protons = 230-90 = 140

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3 years ago
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5 0
3 years ago
The volume density of atoms for a bcc lattice is 5 x 1026 m-3. Assume that the atoms are hard spheres with each atom touching it
ollegr [7]

Explanation:

It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.

This means that volume occupied by 2 atoms is equal to volume of the unit cell.

So, according to the volume density

        5 \times 10^{26} atoms = 1 [tex]m^{3}

        2 atoms = \frac{1 m^{3}}{5 \times 10^{26} atoms} \times 2 atoms

                     = 4 \times 10^{-27} m^{3}

Formula for volume of a cube is a^{3}. Therefore,

           Volume of the cube = 4 \times 10^{-27} m^{3}

As lattice constant (a) = (4 \times 10^{-27} m^{3})^{\frac{1}{3}}

                                   = 1.59 \times 10^{-9} m

Therefore, the value of lattice constant is 1.59 \times 10^{-9} m.

And, for bcc unit cell the value of radius is as follows.

                 r = \frac{\sqrt{3}}{4}a

Hence, effective radius of the atom is calculated as follows.

                 r = \frac{\sqrt{3}}{4}a

                   = \frac{\sqrt{3}}{4} \times 1.59 \times 10^{-9} m

                   = 6.9 \times 10^{-10} m

Hence, the value of effective radius of the atom is 6.9 \times 10^{-10} m.

3 0
3 years ago
How can iodine ( Z = 53) have a higher atomic number yet a lower atomic mass than telluriurn ( Z = 52)?
Leokris [45]

Answer:

Iodine have higher atomic size than tellurium because of the presence of more number of protons and lower atomic mass than tellurium because of the presence of lower number of neutrons.

Explanation:

Atomic number of an element is the number of the protons present in the element.

Atomic mass is the sum of a protons and the neutrons which are present in the nucleus of the atom.

Iodine has higher atomic number than tellurium because it has more number of protons than the tellurium.

On the other hand, iodine has lower atomic mass than tellurium because it has less number of neutrons in its core.

7 0
2 years ago
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