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2 years ago

Need helpppppp hurry pls, i just really need help

Chemistry

1 answer:

mojhsa [17]2 years ago

7 0

Answer:

6.8 mole of O₂

Explanation:

Given expression:

2H₂ + O₂ → 2H₂O

Number of moles of H₂ = 13.6moles

Unknown:

Number of moles of O₂ = ?

Solution:

In the given problem, we are to find the number of moles of oxygen gas that will use up 13.6mole of hydrogen gas;

From the reaction equation;

2 mole of H₂ will completely react with 1 mole of O₂

13.6 moles of H₂ will completely be used up by $\frac{13.6}{2}$ mole of O₂

= 6.8 mole of O₂

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A sample of 23.2 g of nitrogen gas is reacted with

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Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

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2 years ago

Which of the following molecules is responsible for transmitting the energy needed by cells

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Adenosine triphosphate (ATP)

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2 years ago

Read 2 more answers

Which part of the energy profile of a chemical reaction that goes to completion is typically the highest in energy? A. The activ

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The answer is D transition state. In the energy profile, the transition state is the highest point. For a reaction, the activation energy is the minimal energy needed to trigger a reaction. The reactants are the start of the reaction and the products are the end of the reaction.

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2 years ago

Type of Reaction<br> _Mg₃N2 →

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Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

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Answer: The nuclide symbol of X is $^{231}_{90}\textrm{Th}$

Explanation:

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The general equation representing alpha decay process is:

$_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}$

For the given equation :

$^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}$

As the atomic number and mass number must be equal on both sides of the nuclear equation:

$^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}$

Thus the nuclide symbol of X is $^{231}_{90}\textrm{Th}$

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3 years ago