<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
<h3>
Answer: 5</h3>
The coefficient is the term just to the left of the variable. So for the term 5y, the number to the left of y is 5.
extra info: 5y is the same as 5*y or "5 times y", where y is a placeholder for some unknown number.
Using the monthly payments formula, it is found that a car with a value of at most $25,293.
<h3>What is the monthly payment formula?</h3>
It is given by:

In which:
- n is the number of payments.
In this problem, we have that the parameters are given as follows:
A = 400, n = 70, r = 0.035.
Hence:
r/12 = 0.035/12 = 0.002917.
Then we have to solve for P to find the maximum value of the car.


![P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B400%5B%281.002917%29%5E%7B70%7D-1%5D%7D%7B0.002917%281.002917%29%5E%7B70%7D%7D)
P = $25,293.
More can be learned about the monthly payments formula at brainly.com/question/26267630
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Answer:
C
Step-by-step explanation:
Now, what we know is that the total distance from the dormitory to the city is 1 if expressed in fraction. What we need to know is the fraction of the journey that is scheduled as the last part.
We can get this by subtracting the fractions of the first two phases from 1.
This goes as follows:
1 - (1/5) - (2/3) = 2/15
Now, we know that the final 8 kilometers constitute a fraction of just 2/5
Hence, we know that 2/15 of the total journey is 8 kilometers.
Let the total journey distance be T. This means that 2/15 of T is 8km
2/15 * T = 8km
T = ( 8 * 15 )/2 = 120/2 = 60km