$\frac{96}{126}\\\\96\ and\ 126\ are\ even\ numbers\ divisible\ by\ 2\\\\\frac{96:2}{126:2}=\frac{48}{63}\\\\48\ and\ 63\ are\ divisible\ by\ 3,\ because\ 4+8=12(divisible\ by\ 3)\\and\ 6+3=9(divisible\ by\ 3)\\\\\frac{48:3}{63:3}=\boxed{\frac{16}{21}}\leftarrow answer$

5 0

3 years ago

Read 2 more answers

If a rectangle is 30 feet long and the perimeter is 78 feet. What would be the width of the rectangle?

mario62 [17]

Answer:

The width should be 9 feet in this situation

Step-by-step explanation:

(30 x 2) + (9 x 2) =

60 + 18 =

78 ft

78 - (30 X 2) =

78 - 60 =

18 / 2 =

3 0

2 years ago

David and Li made a secret code so they could remember the pattern what should be the next numbers

adell [148]

Do they give you any numbers to start out or to work with?

7 0

3 years ago

(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app

Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads. $P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625$

c) Using Bayes theorem

conditional probability that it wasthe biased coin

= $\frac{0.375}{0.625} \\=\frac{3}{5}$

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin= $\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}$

7 0

2 years ago