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irakobra [83]
3 years ago
8

A certain store has a fax machine available for use by its customers. The store charges $1.60 to send

Mathematics
1 answer:
ryzh [129]3 years ago
8 0
C) 3 pages of fewer
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Express the given quantity as a single logarithm and simplify: 3logx+2log(y-2)-5logx
storchak [24]
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span> 
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span> 
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span> 
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span> 
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Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method. 
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span> 
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Simplify each term<span>. 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span> 

</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span> 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span> 
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Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)

</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span> 
</span>log(x^3(y^2−2y+1)/x^5)

Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>. 
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span> 

</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span> 
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>

Factor<span> by </span>perfect square<span> rule. 
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>

Replace into larger expression<span>. 
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span> 
3 0
3 years ago
See screenshots for question and answer choices.
yawa3891 [41]

Answer:

I belive its 300

Step-by-step explanation:

Brainlist?

3 0
3 years ago
Read 2 more answers
6th grade math ! C: help please
densk [106]

Answer:

9

Step-by-step explanation:

45 Cookies... 5hrs

? cookies... 1 hr

45 ÷ 5 = 9

9 cookies per hour

7 0
2 years ago
What is the range and domain of this question? im unsure​
Naya [18.7K]

Answer:

Step-by-step explanation:

Domain is the independent variable (x)

Range is the dependent variable (y)

For each of these you would just put what x and y are equal to

For the Domain you would put:

0<=x<=3

<= is less than or equal to

For the Range you would put

1<=y<=4

The line is a function

6 0
3 years ago
I need help with this ​
kotegsom [21]

Answer:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

Step-by-step explanation:

Given the table

x   1      3      5      7

y   5      9      13     17

E)

It is clear that there is a CONSTANT CHANGE in the x and y values of the graph.

THE CONSTANT CHANGE IN X VALUES

i.e. 3-1=2, 5-3=2, 7-5=2

THE CONSTANT CHANGE IN Y VALUES

i.e. 9-5 = 4, 13 - 9 = 4, 17 - 13 = 4

Thus, the given table represents the linear function is TRUE

B)

It is clear that the value of y increase as the value of x increases.

Thus, the statement ''the value of y decreases as the value of x increases'' is FALSE!

D)

We know that the slop-intercept form of the line equation is

y = mx+b

where m is the slope and b is the y-intercept.

Determining the equation

Taking two points

(1, 5)

(3, 9)

Finding the slope between (1, 5) and (3, 9)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [9 - 5] / [3 - 1]

               = 4 / 2  

               = 2

Thus, the slope of the line = m = 2

now substituting m = 2 and the point (1, 5) to determine the y-intercept

y = mx+b

5 = 2(1) + b

b = 5-2

b = 3

Thus, the value of y-intercept b = 3

substituting b = 3 and m = 2 in the slope-intercept form

y = mx+b

y = 2x+3

Therefore, the equation for the line function is y = 2x+3 is TRUE

A)

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We already know that the y-intercept b = 3

It means the y-intercept modeled is (0, 3)

Therefore, the statement of the function modeled is (0, 3) is TRUE.

C)

We have already got the equation

y = 2x+3

substituting x = 8

y = 2(8)+3

y = 10+3

y = 13

so at x = 8, the value of y = 13

Therefore, the statement that the ''On a graph of the function when x = 8, the value of y will be 2'' is FALSE!

Conclusion:

Here is the summary of true statements:

A) The statement of the function modeled is (0, 3) is TRUE.

D) the equation for the line function is y = 2x+3 is TRUE.

E) the given table represents the linear function is TRUE

3 0
3 years ago
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