Ask question

Ask question

All categories

anastassius [24]

4 years ago

14

Which part of a feedback mechanism causes change to make up for the departure from the set point? A. sensor B. effector C. respo

nse D. integrating center

2 answers:

koban [17]4 years ago

5 0

I would have to say C. Response.

mylen [45]4 years ago

4 0

I think the answer might be C)

You might be interested in

During the process of condensation, water vapor:____________.

monitta

Answer: (2) releases 2260 J/g of heat energy

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.

Latent heat of condensation is energy released when 1 mole of vapor condenses to form liquid droplets.

The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.

7 0

3 years ago

Why do heart diseas patient's eat oil instead of fat?

7nadin3 [17]

Answer:

lube

Explanation:

8 0

3 years ago

Read 2 more answers

What part of cellular respiration is affected by arsenic

LenaWriter [7]

Answer:

It effects all of the cellular respiration process

Explanation:

It inhibits the Glycolysis. It replaces the phosphate groups that is needed for making Pyruvate and ATP.

5 0

4 years ago

Is water used to test cheese for protein

nekit [7.7K]

Answer:

yes

Explanation:

because it help the body hydrate

7 0

3 years ago

If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te

attashe74 [19]

Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
$pV=nRT$
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
$\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}$

If the supported load is W kg, then
$p_{1} = \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} = 20.3718W \, Pa$
Similarly,
$p_{2} = \frac{4W}{\pi d_{2}^{2}} \, Pa$

$\frac{p_{1}}{p_{2}} = \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}$

Because p₁/p₂ = T₁/T₂, therefore
$16d_{2}^{2} = \frac{293}{423} \\\\ d_{2}^{2} = \frac{0.6927}{16} \\\\ d_{2} = 0.2081 \, m$

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0

4 years ago