Compound 1: Sodium borohydride
In sodium borohydride (NaBH4), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp3 hybridization in NaBH4, to generate 4 hybrid orbitals. These hybrid orbitals, forms sigma bond with 4 'H' atoms. Due to this, the structure of sodium borohydride in tetrahedral.
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Compound 2: B<span>oron trifluoride
</span>In boron trifluoride (BF3), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp2 hybridization in NaBH4, to generate 3 hybrid orbitals. These hybrid orbitals, forms sigma bond with 3 'H' atoms. Due to this, the structure of <span>boron trifluoride</span> is <span>triangular planner</span>.
When you calculate the first two numbers in 493×10
Answer:
The activation energy was reached was 10:45 a.m. The additional energy did not affect the reaction.
Explanation:
Answer:
The final volume of air after compression: V₂ = 4477.63 L = 158.12 cf
Explanation:
Given: Initial gauge pressure of the gas = 0 psi
Initial absolute pressure of the gas: P₁ = gauge pressure + atmospheric pressure = 0 psi + 12.20 psi = 12.20 psi
Initial Temperature = 70°F
⇒ T₁ = (70°F − 32) × 5/9 + 273.15 = 294.26 K
Initial volume of the gas: V₁ = 1200 cf = 1200 × 28.317 = 33980.4 L (∵ 1 cf ≈ 28.317 L)
Final gauge pressure of the gas = 90 psi
Final absolute pressure of the gas: P₂ = gauge pressure + atmospheric pressure = 90 psi + 12.20 psi = 102.2 psi
Final Temperature: T₂ = 125°F
⇒ T₂ = (125°F − 32) × 5/9 + 273.15 = 324.82 K
Final volume of the gas: V₂ = ? L
<u>According to the </u><u>Combined gas law</u><u>:</u>
→
→
→
<u>Therefore, the final volume of air after compression: </u><u>V₂ = 4477.63 L = 158.12 cf</u>