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aliya0001 [1]
3 years ago
6

The fertilizer ammonium sulfate, (nh4)2so4, is prepared by the reaction between ammonia (nh3) and sulfuric acid: 2nh3(g) + h2so4

(aq) ? (nh4)2so4(aq) how many kilograms of nh3 are needed to produce 3.60 × 105 kg of (nh4)2so4?
Chemistry
1 answer:
iren2701 [21]3 years ago
6 0
The chemical reaction would be:

<span>2nh3(g) + h2so4(aq) = (nh4)2so4(aq)
</span>
To determine the ammonia needed, we use the given amount of the product to be produced and use the chemical equation to relate the substances. We do as follows:

3.60 × 105 kg (nh4)2so4 ( 1 kmol / 132.14 kg ) ( 2 kmol NH3 / 1 kmol (nh4)2so4 ) (17.04 kg / 1 kmol ) = 92846.98 kg NH3 needed
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Jen makes a Venn diagram to compare active transport and passive transport.
Oksanka [162]

Answer:

moves molecules

Explanation:

I did this one yesterday! Active transport moves low to high concentration and passive does the opposite so C and D are not an option. Active transport requires energy and Passive Transport does not so it has to be A.!

6 0
3 years ago
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Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
Which of the following elements is most likely to form a +1 charge?<br><br>Cl<br>Mg<br>Na<br>Li
pogonyaev

Answer:

Na

Explanation:

because sodium has 1 electrons so it loses it to be stable and so have positive charge of 1

7 0
3 years ago
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6 Which element requires the least amount of
DaniilM [7]

Which element requires the least amount of

energy to remove the most loosely held electron

from a gaseous atom in the ground state?

<h3>Answer-</h3><h3>Na</h3>
3 0
2 years ago
Read 2 more answers
Help and show work please
olya-2409 [2.1K]
ANWERS ~
We know that :
1 cal (th) = 4.184 J
1 J = 0.2390057361 cal (th) , so :

•55.2 j to cal > 13.193116635 cal
•110 call > 460.24 joule
•65 kj > divide the energy value by 4.184
= 15.535 kilocalories calorie (IT)
——————
Converting form C to F > (F-32)*5/9Understand it better if we have Fahrenheit just add to the equation mentioned to find Celsius.
+to find F to C> (9/5*C)+32

•425 Fahrenheit = (425- 32) × 5/9 =218.33333333 Celsius

•1935 C = 3515 F
———————————-
Converting Celsius to kelvin,We know that :
K = C + 273.15
C = K - 273.15
And from F to K=9/5(F+459.67)
And K to F =(9/5 *k)-459.67
•39.4 Celsius = 312.55 kelvin
•337 Fahrenheit = (337+ 459.67) × 5/9 =442.594 kelvin





4 0
3 years ago
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