Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
<u>Answer:</u>
In an <u>inelastic collision</u> the kinetic energy is not conserved, but <u>the total momentum of the system is conserved</u>.
In other words; the Initial momentum 
is equal to the Final Momentum 
:
Then:
<h2>
</h2>
This means that after the collision the kinetic energy is transformed (dissipated) into another type of energy (caloric energy, for example); and there may be deformation in the blocks.
Therefore, the sentence that best describes this situation is:
<h2>
The total momentum is zero. </h2>
A vasectomy disables a man in making sperm so therefore would not be able to impregnate I woman
Answer:
0.1 m
Explanation:
The closest distance the electrodes used in an NCV test in oerder to measure
the voltage change as a response to the stimulus is 0.1 m.
This is because the shortest observable time period is not less than the action-potential time response of 1 mili second the length traveled by the sensation during this time is 1 m sec x 100 m / s =0.1 m, which is the shortest distance the electrodes could be positioned on the nerve.
