In all chemical reactions, __________ and ____________ must be conserved. energy, matter atoms, heat enthalpy, energy
1 answer:
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Answer:
1.43m
Explanation:
Given data
m1= 50kg
m2=70kg
We are told that Sally m1= 50 sat at one end which is 2m from the center
Hence, the summation of clockwise moment = summation of anticlockwise moment
See the attached image for your reference
50*2= 70*x
100= 70x
x= 100/70
x=1.43m
Hence the mass m2 will be at the 1.43m mark for the net torque to be zero
Answer:
Static friction, F=2.9988 N
Explanation:
Static Friction: It is the friction between two or more solid body that are not moving relative to each other.
When an external force is applied to a body that is in contact with another body, static friction opposes the applied force upto a certain limit, keeping the body at rest. When the applied force exceeds the certain limit the body begins to move. At that moment applied force is equal to limiting value of static friction F.
It varies linearly with normal force(N)
F∝N
F=μN (where μ is constant of proportionality and known as coefficient of static friction)
Now,
Mass, m=1.53 kg
Coefficient of static friction, μ=0.2
Normal force, N=m×g
= (g=9.8 m/s²)
=14.994 N
Static friction, F= μN
=
= 2.9988 N