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serious [3.7K]
3 years ago
9

Run Gizmo: Orbital velocity is the velocity needed to make a circular orbit. Use the Gizmo to find the orbital velocity of the b

all on Venus. Make the orbit as circular as you can.
What is the orbital velocity on Venus?


Do the same on Earth. What is the orbital velocity on Earth?


Based on this, which planet do you think has stronger gravity, Venus or Earth? Explain

This is a science gizmo my science teacher it would rlly help to get answers. Thx.
Physics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

Hmm i need more info

Explanation:

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dado los vectores a=3.5 b=4 c=6.5 , si se sabe que a+b+c=0 (resultante) cual es el angulo formado por A y B?
lawyer [7]

cos(A) = (b2 + c2 − a2) / 2bc = (16+6.5^2-3.5^2)/(2*4*6.5) = 0.88461538  so A = cos−1 (0.88461538) = 27.79 Deg cos(B) = (c2 + a2 − b2)/2ca = (3.5^2+6.5^2-16)/(2*3.5*6.5) = 0.84615385  so B = cos−1 (0.84615385) = 32.2 Deg

6 0
3 years ago
WHAT THE HECK PLEASE HELP HURRY
Angelina_Jolie [31]

i dont know about this but im willing to help you even im a questioneer....

<h2>last choice:blocks 1,2 and 3</h2>

<h3>-questioneer </h3>

comment down below if you know anything about this and explain me so that i can answer it properly

4 0
3 years ago
There are 120 degrees in a straight angle. true false
mixas84 [53]
That would be false.
Straight angle= 180 degrees
Obtuse angle= Above 90, and lower than 180
Acute angle= Below 90
Hope this helps! (:
6 0
3 years ago
Read 2 more answers
A moving particle encounters an external electric field that decreases its kinetic energy from 9970 eV to 6340 eV as the particl
marusya05 [52]

Answer:

q = -1.61x10⁻¹⁷ C

Explanation:

The charge of the particle can be found using the definition of the work done by electric force:  

W = -q\Delta V         (1)

<u>Where</u>:

q: is the charge

ΔV: is the difference in electric potential

The work is also equal to:

W = E_{p_{A}} - E_{p_{B}}    (2)

<u>Where</u>:

E_{p_{A}} and E_{p_{B}} are the electric potential energy of the points A and B, respectively.

Now, by conservation of energy we have:

K_{A} + E_{p_{A}} = K_{B} + E_{p_{B}}     (3)

<u>Where</u>:  

K_{A} and K_{B} are the kinetic energy of the points A and B, respectively.

Rearranging equation (3):  

K_{B} - K_{A} = E_{p_{A}} - E_{p_{B}}      

K_{B} - K_{A} = W

K_{B} - K_{A} = -q\Delta V

Solving the above equation for q:

q = -\frac{K_{B} - K_{A}}{V_{B} - V_{A}} = -\frac{6340 eV - 9970 eV}{19.0 V - 55.0 V} = -100.83 e \cdot \frac{1.6 \cdot 10^{-19} C}{1 e} = -1.61 \cdot 10^{-17} C                                              

Therefore, the charge of the particle is -1.61x10⁻¹⁷ C.

I hope it helps you!

7 0
3 years ago
How to solve 46.7 m/s = ?? Km/h
Gemiola [76]
46.7 m/s in km/h is 168.12 km/h
7 0
3 years ago
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