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serious [3.7K]
3 years ago
9

Run Gizmo: Orbital velocity is the velocity needed to make a circular orbit. Use the Gizmo to find the orbital velocity of the b

all on Venus. Make the orbit as circular as you can.
What is the orbital velocity on Venus?


Do the same on Earth. What is the orbital velocity on Earth?


Based on this, which planet do you think has stronger gravity, Venus or Earth? Explain

This is a science gizmo my science teacher it would rlly help to get answers. Thx.
Physics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

Hmm i need more info

Explanation:

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Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to
SIZIF [17.4K]

Answer:

5 m/s^2

Explanation:

The acceleration of the train is given by:

a=\frac{v-u}{t}

where:

u = 5 m/s is the initial velocity of the train

v = 45 m/s is the final velocity of the train

t = 8 s is the time taken for the train to increase the velocity

Substituting numbers into the formula, we find

a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2

5 0
4 years ago
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Which of the following frequencies falls in the range of RF waves used by commercial radio broadcasting stations?
dybincka [34]
<span>  A. 6,000,000 Hz =3 they were correct</span>
8 0
3 years ago
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Which of the following are likely to form a covalent bond?
sesenic [268]
The answer is
"C"
<span>Magnesium and chlorine</span>
8 0
3 years ago
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A nerve signal travels 150 meters per second. Determine the number of kilometers that the nerve signal will travel in the same t
joja [24]

Explanation:

It is given that,

A nerve signal travels 150 meters per second. It is the speed of the nerve signal. We need to convert the number of kilometers that the nerve signal will travel in the same time.

We know that,

1 kilometer = 1000 meter

1 hour = 3600 seconds

150\ \dfrac{m}{s}=150\times \dfrac{1/1000\ km}{1/3600\ h}

150\ m/s=540\ km/h

So, the nerve signal will travel at the rate of 540 km/h. Hence, this is the required solution.

6 0
3 years ago
A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
docker41 [41]
<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
 s = 6*1^2 + 2*1
 s = 6 + 2
 s = 8 t = 4
 s = 6*t^2 + 2*t s = 6*4^2 + 2*4
 s = 6*16 + 8
 s = 96 + 8
 s = 104
   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
 avg_vel = (104-8)/(4-1) = 96/3 = 32
   And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
6 0
3 years ago
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