cos(A) = (b2 + c2 − a2) / 2bc = (16+6.5^2-3.5^2)/(2*4*6.5) = 0.88461538  so A = cos−1 (0.88461538) = 27.79 Deg
cos(B) = (c2 + a2 − b2)/2ca = (3.5^2+6.5^2-16)/(2*3.5*6.5) = 0.84615385  so B = cos−1 (0.84615385) = 32.2 Deg
  
        
             
        
        
        
i dont know about this but im willing to help you even im a questioneer....
<h2>last choice:blocks 1,2 and 3</h2>
<h3>-questioneer </h3>
comment down below if you know anything about this and explain me so that i can answer it properly
 
        
             
        
        
        
That would be false.
Straight angle= 180 degrees
Obtuse angle= Above 90, and lower than 180
Acute angle= Below 90
Hope this helps! (:
        
                    
             
        
        
        
Answer:
q = -1.61x10⁻¹⁷ C
Explanation:
The charge of the particle can be found using the definition of the work done by electric force:  
 (1)
         (1)
<u>Where</u>:
q: is the charge
ΔV: is the difference in electric potential 
The work is also equal to:
 (2)
    (2)
<u>Where</u>:
 and
 and  are the electric potential energy of the points A and B, respectively.
 are the electric potential energy of the points A and B, respectively.
Now, by conservation of energy we have:
 (3)
      (3)
<u>Where</u>:   
 and
 and  are the kinetic energy of the points A and B, respectively.
 are the kinetic energy of the points A and B, respectively. 
Rearranging equation (3):    
 
      


Solving the above equation for q:
 
                                              
Therefore, the charge of the particle is -1.61x10⁻¹⁷ C.
I hope it helps you!
 
        
             
        
        
        
46.7 m/s in km/h is 168.12 km/h