C that is the condensation point
Answer:
This question is incomplete as it lacks options, the options are:
Which change would be the most effective way to improve the validity of this experiment?
A) Increase the number of goldfish in each tank.
B) Increase the daily amount of food for each tank.
C) Create another group that is fed regular fish food.
D) Increase the number of tanks in each treatment group.
The answer is C
Explanation:
According to this question, an experiment is conducted by Trey to determine which fish food causes the most goldfish activity over a period of two weeks. In this experiment, the independent variable is the FISH FOOD which are; Swift Salmon food and Fast Flounder food. Other variables such as type of gold fish, amount of fish food, amount & type of water etc.
One of the ways to improve an experiment, which is lacking in this case is to have a CONTROL GROUP. Based on the fish foods used for each group, it is obvious that all groups in this experiment are experimental. Hence, creating another group that is fed regular fish food will serve as the CONTROL GROUP in order to compare with the experimental groups. This will improve the validity of the experiment.
Answer:
a.work done=force *displacement
=500N*46m
=23000 Joule
b.power=work done/time taken
=23000/25
=920 watt
c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)
=60kg*9.8m/s*14m
=8232 joule
Explanation:
Because,
In left image pin is not touch to the wire.
In right image pin is touch to the wire.
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Answer:
(a) F = 15.12 N
(b) a = 30.24 m/s²
(c) To Left
Explanation:
(a)
The magnitude of the spring force is given by Hooke's Law as follows:
F = kx
where,
F = Spring Force = ?
k = Spring Constant = 126 N/m
x = Displacement = A = 0.12 m
Therefore,
F = (126 N/m)(0.12 m)
<u>F = 15.12 N</u>
(b)
The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:
F = ma
where,
F = Spring Force = 15.12 N
m = mass of block = 0.5 kg
a = magnitude of acceleration = ?
15.12 N = 0.5 kg (a)
a = 15.12 N/0.5 kg
<u>a = 30.24 m/s²</u>
<u></u>
(c)
Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be <u>to left.</u>
