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Volgvan
4 years ago
8

What are the colors that have lower energy than the color blue

Physics
1 answer:
lubasha [3.4K]4 years ago
3 0
The colour that have lower energy than blue colour is colour red.
There is also a reason behind it.
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All interactions between the atmosphere and the geosphere involve
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The geosphere consists of the solid Earth and the atmosphere consists of the gaseous components in the air. Thus, the answer is C.

Explanation:

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If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the ground after it left the r
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It would take at less 10 minte i guess this the right awnser

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4 years ago
A big olive (* - 0.50 kg) lies at the origin of an xy coordinate system, and a big BrazlI nut (M - 1.5^kg) lie^s at the point (1
Afina-wow [57]

The <em>estimated</em> displacement of the center of mass of the olive is \overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m].

<h3>Procedure - Estimation of the displacement of the center of mass of the olive</h3>

In this question we should apply the definition of center of mass and difference between the coordinates for <em>dynamic</em> (\vec r) and <em>static</em> conditions (\vec r_{o}) to estimate the displacement of the center of mass of the olive (\overrightarrow{\Delta r}):

\vec r - \vec r_{o} = \left[\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot(m_{i}\cdot g + F_{i, x})}{\Sigma \limits_{i =1}^{2}(F_{i,x}+m_{i}\cdot g)} ,\frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot(m_{i}\cdot g + F_{i, y})}{\Sigma \limits_{i =1}^{2}(F_{i,y}+m_{i}\cdot g)} \right]-\left(\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}, \frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}\right) (1)

Where:

  • r_{i, x} - x-Coordinate of the i-th element of the system, in meters.
  • r_{i,y} - y-Coordinate of the i-th element of the system, in meters.
  • F_{i,x} - x-Component of the net force applied on the i-th element, in newtons.
  • F_{i,y} - y-Component of the net force applied on the i-th element, in newtons.
  • m_{i} - Mass of the i-th element, in kilograms.
  • g - Gravitational acceleration, in meters per square second.

If we know that \vec r_{1} = (0, 0)\,[m], \vec r_{2} = (1, 2)\,[m], \vec F_{1} = (0, 3)\,[N], \vec F_{2} = (-3, -2)\,[N], m_{1} = 0.50\,kg, m_{2}  = 1.50\,kg and g = 9.807\,\frac{kg}{s^{2}}, then the displacement of the center of mass of the olive is:

<h3>Dynamic condition\vec{r} = \left[\frac{(0)\cdot (0.50)\cdot (9.807)+(0)\cdot (0) + (1)\cdot (1.50)\cdot (9.807) + (1)\cdot (-3)}{(0.50)\cdot (9.807) + 0 + (1.50)\cdot (9.807)+(-3)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (0)\cdot (3) + (2)\cdot (1.50)\cdot (9.807) +(2) \cdot (-2)}{(0.50)\cdot (9.807) + (3)+(1.50)\cdot (9.807)+(-2)}  \right]\vec r = (0,704, 1.233)\,[m]</h3>

<h3>Static condition</h3><h3>\vec{r}_{o} = \left[\frac{(0)\cdot (0.50)\cdot (9.807) + (1)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807) + (1.50)\cdot (9.807)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (2)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807)+(1.50)\cdot (9.807)}  \right]</h3><h3>\vec r_{o} = \left(0.75, 1.50)\,[m]</h3><h3 /><h3>Displacement of the center of mass of the olive</h3>

\overrightarrow{\Delta r} = \vec r - \vec r_{o}

\overrightarrow{\Delta r} = (0.704-0.75, 1.233-1.50)\,[m]

\overrightarrow{\Delta r} = (-0.046, -0.267)\,[m]

The <em>estimated</em> displacement of the center of mass of the olive is \overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m]. \blacksquare

To learn more on center of mass, we kindly invite to check this verified question: brainly.com/question/8662931

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Best summarizes the law of conservation of energy?
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Official Definition- <span>In physics, the </span>law of conservation of energy<span> states that the total </span>energy<span> of an isolated system remains constant—it is said to be conserved over time. </span>Energy<span> can neither be created nor destroyed; rather, it transforms from one form to another.</span>
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b

Explanation:

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