Bob and Sally sit on a 4 m long see-saw that has its fulcrum smack in the center of the board. If 50 kg Sally is sitting at one
1 answer:
Answer:
1.43m
Explanation:
Given data
m1= 50kg
m2=70kg
We are told that Sally m1= 50 sat at one end which is 2m from the center
Hence, the summation of clockwise moment = summation of anticlockwise moment
See the attached image for your reference
50*2= 70*x
100= 70x
x= 100/70
x=1.43m
Hence the mass m2 will be at the 1.43m mark for the net torque to be zero
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Answer:
We can retain the original diffraction pattern if we change the slit width to d) 2d.
Explanation:
The diffraction pattern of a single slit has a bright central maximum and dimmer maxima on either side. We will retain the original diffraction pattern on a screen if the relative spacing of the minimum or maximum of intensity remains the same when changing the wavelength and the slit width simultaneously.
Using the following parameters: <em>y</em> for the distance from the center of the bright maximum to a place of minimum intensity, <em>m</em> for the order of the minimum, <em>λ </em>for the wavelength, <em>D </em>for the distance from the slit to the screen where we see the pattern and <em>d </em>for the slit width. The distance from the center to a minimum of intensity can be calculated with:
From the above expression we see that if we replace the blue light of wavelength λ by red light of wavelength 2λ in order to retain the original diffraction pattern we need to change the slit width to 2d:
<em> </em>
Answer: 815.51 m
Explanation:
This situation is related to projectile motion or parabolic motion, in which the initial velocity of the bullet has only y-component, since it was fired straight up. In addition, we are dealing with constant acceleration (due gravity), therefore the following equations will be useful to solve this problem:
(1)
(2)
Where:
is the final velocity of the bullet
is the initial velocity of the bullet
is the acceleration due gravity, always directed downwards
is the time
is the vertical position of the bullet at
Let's begin by finding from (1):
(3)
(4)
Now we have to substitute (4) in (2):
(5)
Isolating :
This is the displacement of the bullet after 6.9 s