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3 years ago

Which correctly shows how to use the GCF and the distributive property to find an expression equivalent to 24 + 44?

Mathematics

2 answers:

Darina [25.2K]3 years ago

8 0

The answer is 4(6+11)=which equal 24+44=68

Serggg [28]3 years ago

6 0

24 + 44 = 4(6 + 11) (Answer A)

4(12 + 22) ← 4 is not the greatest, 12 + 22 = 2(6 + 11)

6(4 + 11) ← this is 24 + 66

2(12 + 6) ← this is 24 + 24

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Answer:

$(11\frac{1}{3},20)$

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

$N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40$

$N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}$

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

$N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600$

Thus, the rate of change of sales $N'(x)$ is increasing in the interval $(11\frac{1}{3},20)$ on 10≤x≤40.

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3 years ago

Five more than the product of a number and 8 is equal to 6.

lina2011 [118]

Answer:

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Step-by-step explanation:

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3 years ago

Problem How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?

olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊x⌋ denotes the "floor" of x, meaning the largest integer that is smaller than x)

Then using the inclusion/exclusion principle, there are

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3 years ago

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2 years ago

Read 2 more answers

Hello there can anyone solve this plz (chart is attached):

stich3 [128]

Answer:

$h^\prime(1)=14$

Step-by-step explanation:

We have the function:

$h(x)=f[f(x)]$

And we want to find:

$h^\prime(1)$

So, we will differentiate function h. By the chain rule, this yields:

$h^\prime(x)=f^\prime[f(x)]\cdot f^\prime(x)$

Then it follows that:

$h^\prime(1)=f^\prime[f(1)]\cdot f^\prime(1)$

Using the table, we acquire:

$h^\prime(1)=f^\prime(3)\cdot2$

And using the table again, we acquire:

$h^\prime(1)=7\cdot 2$

Evaluate. Hence:

$h^\prime(1)=14$

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3 years ago