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Levart [38]
3 years ago
12

Twenty percent of a number is equal to 6 less than one half of the same number. What is the number?

Mathematics
1 answer:
Aliun [14]3 years ago
7 0
The number is 20. Work in picture if you want it or want justification of steps:)

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HELP ME PLEASE AND THANK YOU
Anna007 [38]

Answer:

The answer is B

Step-by-step explanation:

5 0
3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ

= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
If a student did not travel to a Spanish-speaking country, how many times more likely is it that the student did not take Spanis
olasank [31]

Answer:

It is 2.2 times as likely.

3 0
3 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.1. This distribution
cluponka [151]

Answer:

Step-by-step explanation:

Hello!

The definition of the Central Limi Theorem states that:

Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

X[bar]≈N(μ;σ²/n)

If the variable of interest is X: the number of accidents per week at a hazardous intersection.

There is no information about the distribution of this variable, but a sample of n= 52 weeks was taken, and since the sample is large enough you can approximate the distribution of the sample mean to normal. With population mean μ= 2.2 and standard deviation σ/√n= 1.1/√52= 0.15

I hope it helps!

5 0
3 years ago
What is 0.2(5x – 0.3) – 0.5(–1.1x + 4.2) simplified? 0.2 [5x + (–0.3)] + (–0.5)(–1.1x + 4.2) x – 2.16
dedylja [7]

0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06

Solution:

Given expression is 0.2(5x – 0.3) – 0.5(–1.1x + 4.2).

To simplify the expression, first multiply the common term within the bracket.

0.2(5x – 0.3) – 0.5(–1.1x + 4.2)

            = (5x × 0.2 – 0.3 × 0.2)  + (–1.1x × (–0.5) + 4.2 × (–0.5))

            = (1x – 0.06) + (5.5x – 2.1)

            = x – 0.06 + 5.5x – 2

Combine like terms together.

            = x + 5.5x – 0.06 – 2

            = 6.5x – 2.06

0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06

Hence the simplified form of 0.2(5x – 0.3) – 0.5(–1.1x + 4.2) is 6.5x – 2.06.

6 0
3 years ago
Read 2 more answers
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