Answer:
The answer is B
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
∫∫8xydA
converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.
So,
∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ
So we integrate r from 0 to 9 and θ from 0 to 2π.
∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ
= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ
= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ
= 8[6561/4]∫(cosθsinθ)dθ
= 13122∫(cosθsinθ)dθ
Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2
Substituting this we have
13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ
= 13122/2[-cos2θ]/2 from 0 to 2π
13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]
= -13122/4[cos4π - cos(0)]
= -13122/4[1 - 1]
= -13122/4 × 0
= 0
Answer:
Step-by-step explanation:
Hello!
The definition of the Central Limi Theorem states that:
Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.
As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.
X[bar]≈N(μ;σ²/n)
If the variable of interest is X: the number of accidents per week at a hazardous intersection.
There is no information about the distribution of this variable, but a sample of n= 52 weeks was taken, and since the sample is large enough you can approximate the distribution of the sample mean to normal. With population mean μ= 2.2 and standard deviation σ/√n= 1.1/√52= 0.15
I hope it helps!
0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06
Solution:
Given expression is 0.2(5x – 0.3) – 0.5(–1.1x + 4.2).
To simplify the expression, first multiply the common term within the bracket.
0.2(5x – 0.3) – 0.5(–1.1x + 4.2)
= (5x × 0.2 – 0.3 × 0.2) + (–1.1x × (–0.5) + 4.2 × (–0.5))
= (1x – 0.06) + (5.5x – 2.1)
= x – 0.06 + 5.5x – 2
Combine like terms together.
= x + 5.5x – 0.06 – 2
= 6.5x – 2.06
0.2(5x – 0.3) – 0.5(–1.1x + 4.2) = 6.5x – 2.06
Hence the simplified form of 0.2(5x – 0.3) – 0.5(–1.1x + 4.2) is 6.5x – 2.06.