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2 years ago

How do I get help on my homework with this app

Mathematics

2 answers:

rosijanka [135]2 years ago

6 0

Answer:

You post your questions

Step-by-step explanation:

Use the search button

Luden [163]2 years ago

4 0

Answer: Just simply put the equation or question up on the page, or even take a picture. Just wait a few minutes and someone should answer it! :)

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Can someone help me with question 11

Aleksandr-060686 [28]

Answer:

no i can not

Step-by-step explanation:

6 0

2 years ago

The Pyraminx is a Rubik's cube-type toy in the shape of a tetrahedron. The Pyraminx shown below has edges 15\,\text{cm}15cm long

____ [38]

Answer:

8.727

Step-by-step explanation:

Since the below edge, d = 15 cm, and the height, h = 12.2 cm, we will use the Pythagorean theorem to find the distance r.

$d^2=r^2+h^2$

$(15)^2 = r^2+(12.2)^2$

$r^2 = (15)^2-(12.2)^2=225-148.84=76.16$

$r=\sqrt{76.16}=8.727$

4 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$