Answer:
v = 0.363 m/s
Explanation:
Given that,
The table is 0.55m tall and the tennis ball lands 0.12m away from the table.
Here, u = 0 (at rest) for initial vertical velocity as it rolls off the edge of a table.
Let t is the time to fall from the vertical height. So,
It can be assumed to find the initial horizontal velocity of the tennis ball. It can be given by :
Hence, the initial horizontal velocity is 0.363 m/s.