What is the minimum work needed to push a 920-kg car 310 m up along a 6.5 ∘incline? Ignore friction.Express your answer using tw
1 answer:
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Answer:
m = 1.5 kg
Explanation:
Data:
- Aceleration (a) = 8 m/s²
- Force (F) = 12 N
- Mass (m) = ?
Use formula:
Replace in the formula:
Equate the newtons:
Simplify m/s²:
It divides:
What is the mass of the train?
The mass of the train is <u>1.5 kilograms.</u>
Answer:
(a) I=0.01 kg.m²
(b) I=0.03 kg.m²
Explanation:
Given data
Mass of disk M=2.0 kg
Diameter of disk d=20 cm=0.20 m
To Find
(a) Moment of inertia through the center of disk
(b) Moment of inertia through the edge of disk
Solution
For (a) Moment of inertia through the center of disk
Using the equation of moment of Inertia
For (b) Moment of inertia through the edge of disk
We can apply parallel axis theorem for calculating moment of inertia