Answer:
2.739 grams of dioxin is present in 3.3 L of this water.
Explanation:
Volume of water , V = 3.3 L = 3.3 × 1000 mL = (1 L = 1000 mL)
Mass of water = m
Density of water =d = 1.00 g/mL
Percentage of dioxon in water = 0.083%
Let the mass of dioxon present in 3300 grams of water be = x
2.739 grams of dioxin is present in 3.3 L of this water.
Answer:
Balanced chemical equations only show formulae, not names. A balancing number, written in normal script, multiplies all the atoms in the substance next to it.
Answer is: <span>1 mol CH</span>₄/<span>16,0 g CH</span>₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 50,6g.
M(CH₄) = 16g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄) = 50,6g ÷16g/mol = 3,16mol.
n(CH₄) : n(CO₂) = 1:1.
nCO₂) = 3,16mol.
m(CO₂) = m(CO₂) · m(CO₂) = 3,16mol · 44g/mol = 139,15g.
M - molar mass.
n - amount of substance.
Answer :
= 108
Explanation
Answer:
Diffusion is driven by differences in concentration. When chemical substances such as perfume are let loose in a room, their particles mix with the particles of air. Diffusion in gases is quick because the particles in a gas move quickly. It happens even faster in hot gases because the particles of gas move faster.
