Answer:
Among given, the ions which are present in the given solution are:
Cu²⁺, Al³⁺ and K⁺
Among given, the ions which are absent in the given solution are:
Pb²⁺, Ca²⁺ and Ba²⁺
The ion which no conclusion is NH₄⁺.
Explanation:
Reagents given are used in salt analysis. The salt analysis is a qualitative analysis used for the identification of cations and anions of inorganic salts.
HCl is used for the identification of group I cations. As no reaction occurred when HCl is added to the solution, that means group I cations are absent.
So, among the given Pb²⁺ is a group I cation, therefore, Pb²⁺ is absent.
H₂S along with HCl is used for the identification group II salts.
Addition of Addition of H₂S with 0.2 M HCl produced a black solid, so, group II cation Cu²⁺ is present.
H₂S is used for the identification of group III cations.
When H₂S is added to the filtrate of group II, white precipitate is formed that means group III cations are present. Among group III cations, Al³⁺ is present.
Addition of (NH₄)₂HPO₄ in the presence of NH₃ is used for the identification of group IV cations.
As no precipitate is formed, therefore, group IV cations are absent.
So among given options, Ca²⁺ and Ba²⁺ are absent in the given solution.
The final supernatant when heated produces purple flame which indicates the presence of K⁺.
Therefore, among given, the ions which are present in the given solution are:
Cu²⁺, Al³⁺ and K⁺
Among given, the ions which are absent in the given solution are:
Pb²⁺, Ca²⁺ and Ba²⁺
The ion which no conclusion is NH₄⁺.
