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Rina8888 [55]
2 years ago
13

Is an alpha a product or reactant when released from an isotope

Chemistry
1 answer:
trasher [3.6K]2 years ago
6 0

Answer:

Alpha decay

Explanation:

That's the definition of alpha decay

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A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub
IgorC [24]

Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

8 0
2 years ago
Which sample of co2 has a definite shape and definite volume
Kisachek [45]
The answer is Solid.

This is on account of the substances that develop a solid are packed in a settled, firmly pressed geometric plan.

4 0
3 years ago
How many electrons does oxygen have in its outer shell?
Ne4ueva [31]
6 . 2 in its inner shell & the remaining 6 in its outer shell.
7 0
3 years ago
How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
Why do some atoms form positive ions and others form negative ions?
Scrat [10]
It is energetically favorable for all atoms to have a complete outer electron shell. Loosely, the atoms on the left hand side of the periodic table only have a few extra electrons in their outer shell so it is energetically favorable for them to lose them. The atoms on the right hand side of the periodic table almost have enough electrons in their outer shell and so they have a tendency to gain them. Once electrons have left an electron shell, an atom will have a positive charge because it has more protons (positive charges) than electrons (negative charges). Similarly, an electron which has gained electrons to complete its outer shell will have a negative charge because it now has more electrons (negative charge) than protons (positive charge).
8 0
3 years ago
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