2 years ago

Is an alpha a product or reactant when released from an isotope

Chemistry

1 answer:

trasher [3.6K]2 years ago

6 0

Answer:

Alpha decay

Explanation:

That's the definition of alpha decay

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Copy and balance these chemical equations "K

alexdok [17]

"K" is Potassium. If that is the answer you are needing.

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2 years ago

How are the ion and isotope different from the atom?

puteri [66]

Ions have an extra or lost an electron. Isotopes have different numbers of neutrons.

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3 years ago

What is the concentration of 10.00mL of HBr if it takes 16.73 mL of a 0.253M LiOH solution to neutralize it?

Fudgin [204]

The chemical reaction would be expressed as follows:

HBr + LiOH = LiBr + H2O

We are given the volumes and corresponding concentration to be used for the reaction. We use these values to solve for the concentration of the other reactant. We do as follows:

0.253 mol LiOH / L solution ( 0.01673 L ) ( 1 mol HBr / 1 mol LiOH ) = 0.00423 HBr needed

Concentration of HBr =0.00423mol / .010 L = 0.423 M HBr

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3 years ago

Question 10

olga2289 [7]

Answer:

Here it would be A,B and C because all the examples are violating safety precautions. They are all examples of un safe signs.

Hope this helps

Explanation:

6 0

2 years ago

The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse

Umnica [9.8K]

Answer : 121.5 μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

 $\frac{N}{ N_{0} } = e^{-( \frac{0.693 X T_{2} }{T_{1}})$

3.8 / $N_{0}$ = $e^$ ((0.693 X 162.5 ) / 32.5) = 121.5

On solving we get, The initial activity as 121.5 μci

5 0

2 years ago

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