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Sveta_85 [38]
3 years ago
12

Newton determined that the attractive force between two masses was DIRECTLY proportional to:

Chemistry
1 answer:
Softa [21]3 years ago
7 0

Answer:

This is Newtons 2nd Law: Force is directly proportional to the acceleration of the object, acceleration is inversely proportional to the mass of the object.

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Why is it important to control the reaction rate of the chemical process
xxTIMURxx [149]
Mg+2HCl=MgCl_2+H_{2(g)}

The reaction creates dihydrogen, hence if it's uncontrolled it could lead to potentially dangerous amounts of gas being released at once.
8 0
3 years ago
How many grams of water in 8.22 grams of cuso4*5h2o?
S_A_V [24]
Molar mass of CuSO4 * 5 H2O 
= 63.546 + 32 + 16*4 + 5*18 
= 249.546 g/mol
 Mass of water in that formula: 5 * 18 = 90 g/mol
Percent by mass of water = 90 / 249.546 = 36%
<span>So, 36% of your 8.22 g is water. 0.36 * 8.22= 2.95 g of water
</span>
8 0
3 years ago
Describe three signs that a chemical reaction has taken place and give an example of each sign
il63 [147K]
Color change, temperature change, bubbling, state change

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7 0
3 years ago
The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to produc
Elis [28]

Answer: 9.9 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{8.150g}{2g/mol}=4.08moles

b) moles of C_2H_4

\text{Number of moles}=\frac{9.330g}{28g/mol}=0.33moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

7 0
3 years ago
How can constraints be used to help define the problem?
vitfil [10]

Answer:

Constraints are restrictions that need to be placed upon variables 

Explanation:

Constraints are restrictions (limitations, boundaries) that need to be placed upon variables used in equations that model real-world situations. It is possible that certain solutions which make an equation true mathematically, may not make any sense in the context of a real-world word problem.

6 0
3 years ago
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