Answer:
f = 1.09 × 10¹⁵ Hz
Explanation:
Given data:
Frequency of wave = ?
Wavelength of wave = 2.73 ×10⁻⁷ m
Solution:
Formula:
Speed of light = frequency × wavelength
speed of light = 3× 10⁸ m/s
by putting values,
3× 10⁸ m/s = f × 2.73 ×10⁻⁷ m
f = 3× 10⁸ m/s / 2.73 ×10⁻⁷ m
f = 1.09 × 10¹⁵s⁻¹
s⁻¹ = Hz
f = 1.09 × 10¹⁵ Hz
The phrase that describes a characteristic of an Arrhenius base is that Arrhenius base add hydroxide ions to the solution ( answer C)
<u><em>Explanation</em></u>
Arrhenius base is a substance that increases the concentration of OH- in aqueous solution.
The Common Arrhenius base are group 1 and 2 hydroxide such as LiOH, NaOH , Ba(OH)2 among others.
for example NaOH dissociate as follows , NaOH → Na+(aq) + OH- (aq)
Answer:
carbon dioxide and water
Explanation:
Example: Combustion of Methane (CH₄(g))
CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)**
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Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,
Ethane (C₂H₆) + O₂ => CO₂(g) + H₂O(g)
Propane (C₃H₈) + O₂ => CO₂(g) + H₂O(g)
Butane (C₄H₁₀) + O₂ => CO₂(g) + H₂O(g)
The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*
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*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.
- Ethane (C₂H₆) + 7/2O₂(g) => 2CO₂(g) + 3H₂O(g)
=> 2C₂H₆ + 7O₂(g) => 4CO₂(g) + 6H₂O(g) <= Standard Form of Rxn
- Propane (C₃H₈) + 5O₂(g) => 3CO₂(g) + 4H₂O(g) <= Standard Form of Rxn (no need to balance with the '2' multiple)
- Butane (C₄H₁₀) + 13/2O₂ => 4CO₂(g) + 5H₂O(g)
=> 2C₃H₈ + 13O₂(g) => 4CO₂(g) + 5H₂O(g) <= Standard Form of Rxn
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**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).
Molarity = moles of solute/volume of solution in liters.
The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.
(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.
Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:
(0.8017 moles NaCl)/(2.2 L) = 0.364 M.
Answer:
joules
Explanation:
it is the measurement of energy
