A material that is a good conductor will be be a poor

4. Water is flowing at 12m/s in a horizontal pipe under a pressure of 600kpa

shusha [124]

Answer:

a. 192 m/s

b. -17,760 kPa

Explanation:

First let's write the flow rate of the liquid, using the following equation:

Q = A*v

Where Q is the flow rate, A is the cross section area of the pipe (A = pi * radius^2) and v is the speed of the liquid. The flow rate in both parts of the pipe (larger radius and smaller radius) needs to be the same, so we have:

a.

A1*v1 = A2*v2

pi * 0.02^2 * 12 = pi * 0.005^2 * v2

v2 = 0.02^2 * 12 / 0.005^2

v2 = 192 m/s

b.

To find the pressure of the other side, we need to use the Bernoulli equation: (600 kPa = 600000 N/m2)

P1 + d1*v1^2/2 = P2 + d1*v2^2/2

Where d1 is the density of the liquid (for water, we have d1 = 1000 kg/m3)

600000 + 1000*12^2/2 = P2 + 1000*192^2/2

P2 = 600000 + 72000 - 1000*192^2/2

P2 = -17760000 N/m2 = -17,760 kPa

The speed in the smaller part of the pipe is too high, the negative pressure in the second part means that the inicial pressure is not enough to maintain this output speed.

4 0

3 years ago

A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta

Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is $99.0m/s^2$

To calculate the distance of rocket, we use third equation of motion, which is:

$v^2-u^2=2as$

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = $99m/s^2$

s = distance = ? m

Putting values in above equation, we get:

$(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters$

3 0

3 years ago

Defination of formula bar

Gekata [30.6K]

The Formula Bar is where data or formulas you enter into a worksheet appear for the active cell. The Formula Bar can also be used to edit data or formula in the active cell. The active cell displays the results of its formula while we see the formula itself in the Formula Bar.

mark me brainliestt :))

7 0

3 years ago

Read 2 more answers

Objects A and B both start at rest. They both accelerate at the same rate. However, object A accelerates for 3x the time as obje

mylen [45]

Answer:

v_Object A = 3v_Object B

OR

1/3v_Object A = v_Object B

Explanation:

Let's see what variables we have in this problem.

Since the objects both start at rest, we have an initial velocity of 0 m/s.

The objects accelerate, so we will have acceleration.

Object A accelerates for 3x the time as Object B, so we have time.

The problem wants us to compare their final speeds, so we have final velocity.

Check what constant acceleration kinematic equation has these variables:

v = v₀ + at

Let's create values for the unknown variables and compare the final velocities.

v = ?
v₀ = 0 m/s (objects start at rest)
a = 5 m/s²
t = 10 s

Since Object A accelerates for 3x the time as Object B, we can use t = 30 s for Object A.

Let's write the two equations:

v = (0) + (5)(10)
v = (0) + (5)(30)

Simplify these equations.

v = 50 m/s
v = 150 m/s

Let's use another set of values to compare the final velocities to see if the velocities differ by 100 m/s or Object A has 3x the final velocity of Object B.

v = ?
v₀ = 0 m/s (objects start at rest)
a = 3 m/s²
t = 7 s

Write the two equations:

v = (0) + (3)(7)
v = (0) + (3)(21)

Simplify these equations.

v = 21 m/s
v = 63 m/s

Now we can clearly see that the final velocities are differed by 3x. Object A has 3x the final speed compared to that of Object B.

3 0

3 years ago

Which of the following is not accurate when desçribing solids?

Kitty [74]

There are no inaccurate items on the list you provided.

And what does 'the following" mean anyway ?

7 0

4 years ago