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Gnesinka [82]
4 years ago
15

Type of psychology that applies psychological knowledge to help solve problems?

Physics
1 answer:
mariarad [96]4 years ago
6 0

Answer: Most definitley teaching, because u need as much knowledge as u can get when trying to teach on the specific subject that u are telling or teaching other ppl.

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Help please :pensive:
tino4ka555 [31]

Answer:

0m/s²

Explanation:

Given parameters:

Initial velocity of the boat = 8m/s

Final velocity  = 8m/s

Time taken  = 4s

Unknown:

Acceleration of the boat = ?

Solution:

Acceleration is the rate of change of velocity with time.

It is mathematically expressed as;

        A = \frac{v - u}{t}

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

    Insert the parameters and solve;

  A = \frac{8-8}{4}   = 0m/s²

6 0
3 years ago
A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the
pantera1 [17]

Answer:

Explanation:

F = k*n

F = 30N

k = ???

N = 0.73 M

F = k* N

30N = k * 0.73

k = 30N / 0.73

k = 41.1

5 0
3 years ago
Time Intervals in Ice Ages
stepladder [879]
It started off with 68% less than it did at the peak, and later created a void and melted the remainder of the ice at about 92%
8 0
3 years ago
Suddenly a worker picks up the bag of gravel. Use energy conservation to find the speed of the bucket after it has descended 2.3
fiasKO [112]

Explanation:

A worker picks up the bag of gravel. We need to find the speed of the bucket after it has descended 2.30 m from rest. It is case of conservation of energy. So,

\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh}

h = 2.3 m

v=\sqrt{2\times 9.8\times 2.3} \\\\v=6.71\ m/s

So, the speed of the bucket after it has descended 2.30 m from rest is 6.71 m/s.

8 0
3 years ago
If a roller coaster train has a potential energy of 1,500 J and a kinetic energy of 500 J as it starts to travel downhill, its t
Lina20 [59]
E_{total} = KE + PE \\ KE = 500 J \\ PE = 1500 J \\ E_{total} = 500J + 1500J \\ E_{total} = 2000J
4 0
4 years ago
Read 2 more answers
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