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Elanso [62]
3 years ago
10

The number to the right of an element's symbol (ex. C-12) identifies the _____ of an isotope. A. atomic mass B. mass number C. a

tomic mass unit D. average atomic mass
Chemistry
2 answers:
OverLord2011 [107]3 years ago
7 0

Answer:

Atomic Mass

Explanation:

it is also sometimes below the symbol of the element :)

NeX [460]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

Atomic mass is defined as the summation of total number of protons and neutrons present in an element.

For example, in ^{12}C the number 12 represents the total number of protons and neutrons present in it.

As it is known that an atom of carbon always contains 6 protons but it can hold different number of neutrons.

Hence, in ^{12}C the number 12 represents the atomic mass.

Therefore, we can conclude that the number to the right of an element's symbol (ex. C-12) identifies the atomic mass.

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What is the correct equilibrium constant
Ksju [112]

Answer:

(CO2)+(CF)/ (COF)².

Explanation:

k=

6 0
3 years ago
The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
3 years ago
Read 2 more answers
What kind of chemical reaction does the chemical equation sodium + chlorine → sodium chloride represent?
Vinil7 [7]
D. Synthesis cause A + B --> AB Equation: 2Na + Cl2 --> 2NaCl
7 0
3 years ago
Read 2 more answers
Complete the equation for the dissociation of Na2CO3(aq).Omit water from the equation because it is understood to be present.
ozzi

Answer:

Na2CO3 <==> 2Na^+ + CO3^2-

Explanation:

6 0
3 years ago
The molar mass of an unknown gas was measured by an effusion experiment. It was found that it took 60 s for the gas to effuse, w
Marizza181 [45]

Answer:

The molar mass of the gas is 44 g/mol

Explanation:

It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:

\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }

If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):

\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }

6,61 = √M₂

44g/mol = M₂

<em>The molar mass of the gas is 44 g/mol</em>

<em></em>

I hope it helps!

4 0
3 years ago
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