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zalisa [80]
2 years ago
8

What are the rules for naming hydrocarbons?

Chemistry
1 answer:
GrogVix [38]2 years ago
3 0

Answer:

IUPAC Rules for Alkane Nomenclature

Find and name the longest continuous carbon chain.

Identify and name groups attached to this chain.

Number the chain consecutively, starting at the end nearest a substituent group.

Designate the location of each substituent group by an appropriate number and name.

Explanation:

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Are all the atoms in the same plane for cyclohexanone.
vovangra [49]

Answer:

the atoms in cyclohexanone are not in the same

Explanation:

but they are in a benzene ring! Cyclohexane has only sigma bonded carbons with bonds that stick out of the plane

7 0
2 years ago
What is 2(NH,4)Cr,2 O,7
Vitek1552 [10]

oxidation-reduction.


4 0
3 years ago
A mixture of NaCl and CuCO3 was dissolved in water and the resulting slurry was filtered in to a beaker. The beaker and the filt
Firdavs [7]

The percentage adds up to 100%.

<h3>Percentages</h3>

Mass of mixture = mass of container+mixture - mass of container = 56.779 - 54.558 = 2.221 g

CuCO3 is insoluble in water. Thus:

Mass of CuCO3 = mass of beaker and residue - mass of beaker = 78.875 - 77.575 = 1.300 g

Mass of NaCl = mass of mixture - mass of CuCO3 = 2.221 - 1.300 = 0.921 g

%NaCl (w/w) = weight of NaCl/weight of mixture = 10.921/2.221 = 41.468%

% (w/w) CuCO3 = weight of CuCO3/weight of mixture = 1.300/2.221 = 58.532%

Addition of percentages = 41.468 + 58.532 = 100%

More on percentages can be found here: brainly.com/question/24159063

#SPJ1

6 0
2 years ago
Identify the products in the reaction HCl+NaOH=NaCl+H2O
valentina_108 [34]

NaCl and H2O.

The products are typically the elements/compounds on the right side of the equation or the right side of the arrow. The left side of the arrow would be the reactants of the equation.

Hope this helps!

5 0
3 years ago
How is electron movement related to the bonding in sodium chloride?
stepladder [879]
Cl is highly electronegative and will actually pull away 1 electron from sodium, forming an ionic bond. 
5 0
3 years ago
Read 2 more answers
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