<h3>1. <u>Answer;</u></h3>
Percentage yield = 65.9%
<h3><u>Explanation;</u></h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
Therefore;
- Percentage yield = Actual yield/theoretical yield × 100%
= (1.20 g/1.82 g) × 100%
= 65.9%
<h3 /><h3>2. <u>Answer;</u></h3>
The amount of measured yield over calculated yield
<h3>Explanation;</h3>
- Percentage yield of a reaction is obtained by dividing the actual yield by theoretical yield and multiplying by 100 percent.
- The actual yield is the actual amount produced when the experiment or reaction is carried out.
- Theoretical yield is the calculated or expected amount of the product. It is based on the limiting reactant.
<h3>3. <u>Answer</u>;</h3>
= 37.71 g
<h3><u>Explanation;</u></h3>
The balanced equation is:
2 Na + Cl₂ → 2 NaCl.
From the balanced equation:
2.0 moles of Na reacts with 1.0 mole of chlorine gas to give 2.0 moles of NaCl.
- The number of moles of Na = mass/atomic mass),
n = (17.25 g / 22.989 g/mole of Na)
= 0.75 moles
Thus;
- Using cross multiplication and from the equation:
2.0 moles of Na → 2.0 moles of NaCl
0.75 moles of Na → 0.75 moles of NaCl
Therefore;
- The mass of the produced NaCl (m = n x molar mass)
m = (0.75 mole x 58.443 g/mole of NaCl)
= 43.85 g.
- This is the yield if the percentage of yield is 100%, but the percentage yield of the reaction is 86%.
Hence;
The actual yield = (43.85 g) (86/100)
= 37.71 g.
<h3>4. <u>Answer;</u></h3>
Oxygen and hydrogen molecules will mix because of random movement of their molecules.
<h3><u>Explanation;</u></h3>
- Both gasses will diffuse into the other jar until the molecules are well distributed into both containers.
- Diffusion is the movement of molecules from a point of high concentration to areas of low concentration until equilibrium is attained.
- The mixture of gases will have a partial pressure that is equal to the sum of the partial pressures of the component gases.