Answer:

Step-by-step explanation:



Answer:
3.4 gigabytes
Step-by-step explanation:
Because 57.20$ divided by 47 is 10.20 and 3 goes in to 10.2 3.4 times.
Answer: 800
Divide 3200 by 4 to get 800.
Answer:
it would be b
Step-by-step explanation:
For this case we have the following quadratic equation:

Where:

Its roots will be given by:

The roots are:

Answer:
