Answer:
CH4
Explanation:
In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.
Hence we can now say;
If 163 g of the compound contains 6.13 ×10^24 molecules
x g will contain 6.02 × 10^23 molecules
x= 163 × 6.02 × 10^23 / 6.13 × 10^24
x= 981.26 × 10^23/ 6.13 ×10^24
x= 160.1 × 10^-1 g
x= 16.01 g
x= 16 g(approximately)
16 g is the molecular mass of methane hence x must be methane (CH4)
Answer:
82.24% percent composition of N and 17.76% percent composition of H .
Explanation:
The Earth's early atmosphere consisted of Carrbon Dioxide, methane, sulphur, ammonia, nitrogen and smaller amounts (aprox. 0.05%) of other gases.
Answer:
pH= 12.7
Explanation:
a)Keep an emergency kit and fresh water in your car in the event of _an unexpected event.
b) pOH= -log[OH-]
pOH= -log[5.00×10^-2]
pOH= 1.3
But pH+pOH= 14
pH= 14-pOH= 14-1.3
pH= 12.7
PV=nRT<=> P=nRT/V=2,40*R*(273+97)/45 atm.
Calculate it. R is a number that is given, find it and use your math to solve.
