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chubhunter [2.5K]
2 years ago
13

In general, a catalyst speeds up a given reaction by providing an alternative mechanism that has a ______ activation energy, thu

s ______ the rate constant and the overall rate. Multiple choice question.
Chemistry
1 answer:
prisoha [69]2 years ago
5 0

Answer:

lower; increasing

Explanation:

hope this helps :)

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Define the terms heredity and inherited in your own words.
adelina 88 [10]

Answer:

Heredity is when you have gotten either physical or mental traits from your parents.

Inherited in Biology: Getting traits from your parents

Inherited outside Biology: is the practice of passing on private property, titles, debts, privileges, rights, and obligations upon the death of an individual.

Explanation:

3 0
3 years ago
Seawater has a ph of 8.1. what is the concentration of oh–?
lara31 [8.8K]
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1 
pOH = 5.9 
pOH is used to calculate the hydroxide ion concentration 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M
4 0
3 years ago
Calculate the mass of grams of 14.79ml of a substance. It'd density is 1.193gml
Alisiya [41]
<span>D=m/v

Given:
d=1.193g/ml
v= 14.79ml

Solution
m=dv
m=1.193g/ml x 14.79ml

m= 17.644g

Density is the mass per volume of the material. Basically, it refers to the measurement of how crammed together is the matter. The formula to calculate density is rho = m/v wherein rho is the density, m stands for the mass and v stands for the volume.</span>
8 0
3 years ago
Need to complete the chart
GalinKa [24]

Answer:

Row 1

[H^+]=1.8\times 10^{-6}M

pH=-\log[H^+]=-\log[1.8\times 10^{-6}]=5.7

pOh=14-pH=14-5.7=8.3

pOH=-\log[OH^-]

[OH^-]=0.5\times 10^{-8}M

Hence, acidic

Row 2

[OH^-]=3.6\times 10^{-10}M

pOH=-\log[OH^-]=-\log[3.6\times 10^{-10}]=9.4

pH=14-pOH=14 - 9.4 = 4.6

pH=-\log[H^+]

[H^+]=2.6\times 10^{-5}M

Hence, acidic

Row 3

pH = 8.15

[H^+]=0.7\times 10^{-8}M

pOH=14-pH=14 - 8.15 = 5.8

pOH=-\log[OH^-]

[OH^-]=1.5\times 10^{-6}M

Hence, basic

Row 4

pOH = 5.70

[OH^-]=1.8\times 10^{-6}M

pH=14-pOH=14 - 5.70 = 8.3

pH=-\log[H^+]

[H^+]=0.5\times 10^{-8}M

Hence, basic



3 0
4 years ago
[?] describes how small molecules can be selectively removed from a colloidal suspension while retaining large molecules.
IceJOKER [234]
Dialysis is correct……………
7 0
1 year ago
Read 2 more answers
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