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Igoryamba
4 years ago
15

What is the product of the second alpha decay in this series

Chemistry
1 answer:
Valentin [98]4 years ago
7 0

In Alpha decay two neutrons and protons are lost, so the mass decreases by four and the atomic number decreases by two.

Therefore the correct answer is B: Ra-224.

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Which of the following elements exist naturally as a covalently bonded molecule?
mr Goodwill [35]
I think that it's D.
4 0
3 years ago
How many grams of O2 are present in 44.1 L of O2 at STP?
ycow [4]

Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

First of all, the STP conditions refer to the standard temperature and pressure, where the values ​​used are: pressure at 1 atmosphere and temperature at 0°C. These values ​​are reference values ​​for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature.
  • R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
  • n is the number of moles of the gas.

Then, in this case:

  • P= 1 atm
  • V= 44.1 L
  • n= ?
  • R= 0.082 \frac{atmL}{molK}
  • T= 0°C =273 K

Replacing in the expression for the ideal gas law:

1 atm× 44.1 L= n× 0.082 \frac{atmL}{molK}× 273 K

Solving:

n=\frac{1 atm x44.1 L}{0.082\frac{atmL}{molK}x273K}

n=1.97 moles

Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:

1.97 molesx\frac{32 g}{1 mole}= 63.04 g ≈ <u><em>63 g</em></u>

Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

Learn more about the ideal gas law:

  • <u>brainly.com/question/4147359?referrer=searchResults</u>
7 0
3 years ago
In the double replacement reaction between na2so4 (aq) and bacl2 (aq), will a precipitate form?
bagirrra123 [75]
A precipitate will form since BaSO₄ is insoluble in water.
8 0
4 years ago
Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. P
pantera1 [17]

Answer:

The mass of P₄O₁₀ (s) formed is 471.03 g

Explanation:

4PH₃(g) + 8O₂(g) →  P₄O₁₀ (s)  + 6H₂O (g)

This is the ballanced equation.

Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.

Moles of PH₃ = Mass PH₃ / Molar mass PH₃

Moles PH₃ = 225 g / 33.9 g/m

Moles PH₃ = 6.63 moles

So the rule of three, will be:

If 4 moles of PH₃ generate 1 mol  P₄O₁₀

Then, 6.63 moles of  PH₃ generate (6.63  .1)/4 = 1.66 moles

If we want to know the mass:

Moles . Molar mass = mass

Molar mass  P₄O₁₀  = 283.88 g/m

1.66m  . 283.88 g/m = 471.03 g

3 0
3 years ago
A line graph shows the relationship between three variables true or false
Nookie1986 [14]
The answer would be B) False cause a line graph only shows ''two'' variables, not three.
6 0
3 years ago
Read 2 more answers
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