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Tcecarenko [31]
3 years ago
5

Which statement describes a similarity between conductors and insulators?

Chemistry
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

They can both be used in an electric circuit.

Explanation:

Though conductors and insulators are very different from each other but still they have a similarity that "they can both be used in an electric circuit".

Conductors are the material that allows electricity to flow and insulators have high resistance and do not allow electricity to flow.

Both conductors and insulators are used in an electric circuit as conductor is used in wires, batteries and bulb to flow current while insulators are used in insulation of wire, switches, plugs and etc. Combination of them makes the circuit shock free.

Hence, the correct answer is "They can both be used in an electric circuit."

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Consider the hypothetical reaction 3A + 4B → C + 2D Over an interval of 2.50 s the average rate of change of the concentration o
faust18 [17]

Answer:

Final [B] = 1.665 M

Explanation:

3A + 4B → C + 2D

Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

0.05600 M/s = 4 [B]/ 2.50 s

[B] = 0.035 M (concentration of B consumed)

Final [B] = initial [B] - consumed [B]

Final [B] = 1.700 M - 0.035 M

Final [B] = 1.665 M

3 0
2 years ago
What is a chromosome
erica [24]
A chromosome is a tightly coiled X of genetic material that has genes on it.
Hope this helps!

4 0
3 years ago
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Which of the following is the ground state of an atom? Which is its excited state? Which is an impossible electron configuration
Rus_ich [418]

For this specific problem, these would be the answer to the following choices:

a. excited

b. ground

c. impossible

I am hoping that these answers have satisfied your queries and it will be able to help you, thank you and have a nice day.

3 0
3 years ago
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What is the decay mode of radium-226?
inn [45]

Answer:

Radium-226 is a radioactive decay product in the uranium-238 decay series and is the precursor of radon-222. Radium-228 is a radioactive decay product in the thorium-232 decay series. Both isotopes give rise to many additional short-lived radionuclides, resulting in a wide spectrum of alpha, beta and gamma radiations.

6 0
3 years ago
Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

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2 years ago
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