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aivan3 [116]
3 years ago
14

A cube of copper has a temperature of 5°C. The cube is placed in a closed container whose internal temperature is 85°C. What wil

l happen over time?
Heat will flow from the cube into the air in the container.


Heat will flow from the air in the container into the cube.
Chemistry
2 answers:
ddd [48]3 years ago
5 0

Answer: Heat will flow from the air in the container into the cube.

Part 2. When the temperatures of the cube and the container are equal.

Explanation:

i got it correct on edge

Assoli18 [71]3 years ago
3 0

Answer:

Heat will flow from the air in the container into the cube.

Explanation:

Heat flows from<em> places with higher</em> temperature to <em>places with lower </em>temperature.

With that information in mind then we can see that the cube of copper has a lower temperature than the air in the container (85°C > 5°C), thus heat will flow into the cube.

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Answer:

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Explaination:

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2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

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Explanation:

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