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aivan3 [116]
3 years ago
14

A cube of copper has a temperature of 5°C. The cube is placed in a closed container whose internal temperature is 85°C. What wil

l happen over time?
Heat will flow from the cube into the air in the container.


Heat will flow from the air in the container into the cube.
Chemistry
2 answers:
ddd [48]3 years ago
5 0

Answer: Heat will flow from the air in the container into the cube.

Part 2. When the temperatures of the cube and the container are equal.

Explanation:

i got it correct on edge

Assoli18 [71]3 years ago
3 0

Answer:

Heat will flow from the air in the container into the cube.

Explanation:

Heat flows from<em> places with higher</em> temperature to <em>places with lower </em>temperature.

With that information in mind then we can see that the cube of copper has a lower temperature than the air in the container (85°C > 5°C), thus heat will flow into the cube.

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Answer:

B. 4 ml

Explanation:

Volume displacement of the hammer = volume volume of water when the hammer was placed into the cylinder - volume of water only before the hammer was placed into the cylinder.

Volume volume of water when the hammer was placed into the cylinder = 69 ml

Volume of water only before the hammer was placed into the cylinder = 65 ml

Volume displacement of the hammer = 69 ml - 65 ml = 4 ml

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What two terms are used to describe the temperature at which solids and liquids of the same substance exist at the same time?
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The answer is melting and freezing point.

Explanation:

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In the laboratory, a quantity of I2 was reacted with excess H2 to give 1.26 moles of HI. It is also known that the percent yield
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Answer:

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Explanation:

Hello,

This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.

Percent yield = (actual yield / estimated yield) × 100

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Estimated yield = ?

Percentage yield = 84%

84 / 100 = 1.2 / x

Cross multiply and solve for x

100x = 84 × 1.2

100x = 100.8

x = 100.8/100

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a property whose value does not depend on the path taken to reach that specific value.

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