Creating a prototype and troubleshooting are steps in the development of?

2 answers:

8 0

Your answer is a new experiment, since it's something that hasn't been tried before, or has, but resulted in with lots of errors.

Zigmanuir [339]3 years ago

7 0

Answer:

Im not the surest of what the answer is but it's not "a new expirement" for anyone thats wondering.

Explanation:

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A stone with a mass m is dropped from an airplane that has a horizontal velocity v at a height h above a lake. If air resistance

seropon [69]

Answer: Option B. R = (1/2)gt^2

Explanation:

S = R (horizontal distance)

V^2 = 2gS

V^2 = 2gR

R = V^2 / 2g

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R = (g^2 x t^2) / 2g

R = gt^2 / 2

But t^2 = 2h/g

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R = h

But h = (1/2)gt^2

R = h = (1/2)gt^2

4 0

3 years ago

It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w

Charra [1.4K]

Answer:

b) q large and m small

Explanation:

q is large and m is small

We'll express it as :

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As we know the formula:

F = Eq

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F = Bqv

F = $\frac{mv^{2} }{r}$

Bqv = $\frac{mv^{2} }{r}$

or Eq = $\frac{mv^{2} }{r}$

Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.

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3 years ago

A parallel-plate capacitor is constructed from two aluminum foils of 1 square centimeter area each placedon both sides of a rubb

Svet_ta [14]

Answer:

The voltage will be 0.0125V

Explanation:

See the picture attached