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nydimaria [60]
3 years ago
6

A cat with mass 4.0 kg jumps down to the floor from a bookcase 2.0 m high. What is the cat's change in

Physics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:

-78 J

Explanation:

I just answered that question.

eduard3 years ago
3 0

Answer: -7J

Explanation:

To determine the change in potential energy, use the equation ΔPE=mgΔh

Δ

PE=mg

Δ

h

, where m is the mass, g= 9.8 m/s2

g= 9.8 m/s

2

, and Δh is the change in height. Hence, we have that the potential energy PE=4.0 kg×9.8 m/s2×-2.0 m=-78 J

PE=4.0 kg

×

9.8 m/s

2

×

-2.0 m=-78 J

. To verify that this is correct, note that since the cat changes the potential energy to kinetic energy by jumping, the potential energy decreases. Hence, the potential energy should be negative.

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A 3 kg rock sits on a 0.8 meter ledge. If it is pushed off, how fast will it be going at the bottom?
andrey2020 [161]

As long as it sits on the shelf, its potential energy
relative to the floor is . . .

   Potential energy =      (mass) x (gravity) x (height) =

                                       (3 kg) x (9.8 m/s²) x (0.8m) = <u>23.52 joules</u> .

If it falls from the shelf and lands on the floor, then it has exactly that
same amount of energy when it hits the floor, only now the 23.52 joules
has changed to kinetic energy.

   Kinetic energy =                                          (1/2) x (mass) x (speed)²

                                                 23.52 joules = (1/2) x (3 kg) x (speed)²

Divide each side by  1.5 kg :     23.52 m²/s² = speed²

Take the square root of each side:    speed = √(23.52 m²/s²) =  <em>4.85 m/s </em> (rounded)


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